This example shows a problem by Miroslav Havel. The key 1. Bc5!! gives a flight square for the black king and threatens 2.Rxf6+ Ke4 3.Nf2# with a model mate. The main variations end with model mates from white batteries:
There are several other variations (after 1...Ne4 and 1...Ke6), which do not end with model mates, and allow for multiple continuations. In the Bohemian school they are irrelevant, as long as they end with a mate in a prescribed number of moves.
This example shows a helpmate, in which both sides cooperate to achieve a mate to the black king. It has two solutions ending in model mates (Black moves first in helpmates):
If all units of both colours are involved in a model mate, then it is an ideal mate. Both mates in the presented helpmate are ideal mates.