Suppose that f {\displaystyle f} is analytic and injective in the punctured open unit disk D ∖ { 0 } {\displaystyle \mathbb {D} \setminus \{0\}} and has the power series representation
then the coefficients a n {\displaystyle a_{n}} satisfy
The idea of the proof is to look at the area uncovered by the image of f {\displaystyle f} . Define for r ∈ ( 0 , 1 ) {\displaystyle r\in (0,1)}
Then γ r {\displaystyle \gamma _{r}} is a simple closed curve in the plane. Let D r {\displaystyle D_{r}} denote the unique bounded connected component of C ∖ γ r ( [ 0 , 2 π ] ) {\displaystyle \mathbb {C} \setminus \gamma _{r}([0,2\pi ])} . The existence and uniqueness of D r {\displaystyle D_{r}} follows from Jordan's curve theorem.
If D {\displaystyle D} is a domain in the plane whose boundary is a smooth simple closed curve γ {\displaystyle \gamma } , then
provided that γ {\displaystyle \gamma } is positively oriented around D {\displaystyle D} . This follows easily, for example, from Green's theorem. As we will soon see, γ r {\displaystyle \gamma _{r}} is positively oriented around D r {\displaystyle D_{r}} (and that is the reason for the minus sign in the definition of γ r {\displaystyle \gamma _{r}} ). After applying the chain rule and the formula for γ r {\displaystyle \gamma _{r}} , the above expressions for the area give
Therefore, the area of D r {\displaystyle D_{r}} also equals to the average of the two expressions on the right hand side. After simplification, this yields
where z ¯ {\displaystyle {\overline {z}}} denotes complex conjugation. We set a − 1 = 1 {\displaystyle a_{-1}=1} and use the power series expansion for f {\displaystyle f} , to get
(Since ∫ 0 2 π ∑ n = − 1 ∞ ∑ m = − 1 ∞ m r n + m | a n | | a m | d θ < ∞ , {\displaystyle \int _{0}^{2\pi }\sum _{n=-1}^{\infty }\sum _{m=-1}^{\infty }m\,r^{n+m}\,|a_{n}|\,|a_{m}|\,d\theta <\infty \,,} the rearrangement of the terms is justified.) Now note that ∫ 0 2 π e i ( m − n ) θ d θ {\displaystyle \int _{0}^{2\pi }e^{i\,(m-n)\,\theta }\,d\theta } is 2 π {\displaystyle 2\pi } if n = m {\displaystyle n=m} and is zero otherwise. Therefore, we get
The area of D r {\displaystyle D_{r}} is clearly positive. Therefore, the right hand side is positive. Since a − 1 = 1 {\displaystyle a_{-1}=1} , by letting r → 1 {\displaystyle r\to 1} , the theorem now follows.
It only remains to justify the claim that γ r {\displaystyle \gamma _{r}} is positively oriented around D r {\displaystyle D_{r}} . Let r ′ {\displaystyle r'} satisfy r < r ′ < 1 {\displaystyle r<r'<1} , and set z 0 = f ( r ′ ) {\displaystyle z_{0}=f(r')} , say. For very small s > 0 {\displaystyle s>0} , we may write the expression for the winding number of γ s {\displaystyle \gamma _{s}} around z 0 {\displaystyle z_{0}} , and verify that it is equal to 1 {\displaystyle 1} . Since, γ t {\displaystyle \gamma _{t}} does not pass through z 0 {\displaystyle z_{0}} when t ≠ r ′ {\displaystyle t\neq r'} (as f {\displaystyle f} is injective), the invariance of the winding number under homotopy in the complement of z 0 {\displaystyle z_{0}} implies that the winding number of γ r {\displaystyle \gamma _{r}} around z 0 {\displaystyle z_{0}} is also 1 {\displaystyle 1} . This implies that z 0 ∈ D r {\displaystyle z_{0}\in D_{r}} and that γ r {\displaystyle \gamma _{r}} is positively oriented around D r {\displaystyle D_{r}} , as required.
The inequalities satisfied by power series coefficients of conformal mappings were of considerable interest to mathematicians prior to the solution of the Bieberbach conjecture. The area theorem is a central tool in this context. Moreover, the area theorem is often used in order to prove the Koebe 1/4 theorem, which is very useful in the study of the geometry of conformal mappings.