Power gain, in decibels (dB), is defined as follows:
where P in {\displaystyle P_{\text{in}}} is the power applied to the input, P out {\displaystyle P_{\text{out}}} is the power from the output.
A similar calculation can be done using a natural logarithm instead of a decimal logarithm, resulting in nepers instead of decibels:
The power gain can be calculated using voltage instead of power using Joule's first law P = V 2 / R {\displaystyle P=V^{2}/R} ; the formula is:
In many cases, the input impedance R in {\displaystyle R_{\text{in}}} and output impedance R out {\displaystyle R_{\text{out}}} are equal, so the above equation can be simplified to:
This simplified formula, the 20 log rule, is used to calculate a voltage gain in decibels and is equivalent to a power gain if and only if the impedances at input and output are equal.
In the same way, when power gain is calculated using current instead of power, making the substitution P = I 2 R {\displaystyle P=I^{2}R} , the formula is:
In many cases, the input and output impedances are equal, so the above equation can be simplified to:
This simplified formula is used to calculate a current gain in decibels and is equivalent to the power gain if and only if the impedances at input and output are equal.
The "current gain" of a bipolar transistor, h FE {\displaystyle h_{\text{FE}}} or h fe {\displaystyle h_{\text{fe}}} , is normally given as a dimensionless number, the ratio of I c {\displaystyle I_{\text{c}}} to I b {\displaystyle I_{\text{b}}} (or slope of the I c {\displaystyle I_{\text{c}}} -versus- I b {\displaystyle I_{\text{b}}} graph, for h fe {\displaystyle h_{\text{fe}}} ).
In the cases above, gain will be a dimensionless quantity, as it is the ratio of like units (decibels are not used as units, but rather as a method of indicating a logarithmic relationship). In the bipolar transistor example, it is the ratio of the output current to the input current, both measured in amperes. In the case of other devices, the gain will have a value in SI units. Such is the case with the operational transconductance amplifier, which has an open-loop gain (transconductance) in siemens (mhos), because the gain is a ratio of the output current to the input voltage.
Q. An amplifier has an input impedance of 50 ohms and drives a load of 50 ohms. When its input ( V in {\displaystyle V_{\text{in}}} ) is 1 volt, its output ( V out {\displaystyle V_{\text{out}}} ) is 10 volts. What is its voltage and power gain?
A. Voltage gain is simply:
The units V/V are optional but make it clear that this figure is a voltage gain and not a power gain. Using the expression for power, P = V2/R, the power gain is:
Again, the units W/W are optional. Power gain is more usually expressed in decibels, thus:
A gain of factor 1 (equivalent to 0 dB) where both input and output are at the same voltage level and impedance is also known as unity gain.
Graf, Rudolf F. (1999). Modern Dictionary of Electronics (7 ed.). Newnes. p. 314. ISBN 0080511988. 0080511988 ↩
Basu, Dipak (2000). Dictionary of Pure and Applied Physics. CRC Press. p. 157. ISBN 1420050222. 1420050222 ↩
Bahl, Inder (2009). Fundamentals of RF and Microwave Transistor Amplifiers. John Wiley and Sons. p. 34. ISBN 978-0470462317. 978-0470462317 ↩
White, Glenn; Louie, Gary J (2005). The Audio Dictionary (3 ed.). University of Washington Press. p. 18. ISBN 0295984988. 0295984988 ↩