Main article: Area theorem (conformal mapping)
Suppose that
is univalent in | z | > 1 {\displaystyle |z|>1} . Then
In fact, if r > 1 {\displaystyle r>1} , the complement of the image of the disk | z | > r {\displaystyle |z|>r} is a bounded domain X ( r ) {\displaystyle X(r)} . Its area is given by
Since the area is positive, the result follows by letting r {\displaystyle r} decrease to 1 {\displaystyle 1} . The above proof shows equality holds if and only if the complement of the image of g {\displaystyle g} has zero area, i.e. Lebesgue measure zero.
This result was proved in 1914 by the Swedish mathematician Thomas Hakon Grönwall.
The Koebe function is defined by
Application of the theorem to this function shows that the constant 1 / 4 {\displaystyle 1/4} in the theorem cannot be improved, as the image domain f ( D ) {\displaystyle f(\mathbf {D} )} does not contain the point z = − 1 / 4 {\displaystyle z=-1/4} and so cannot contain any disk centred at 0 {\displaystyle 0} with radius larger than 1 / 4 {\displaystyle 1/4} .
The rotated Koebe function is
with α {\displaystyle \alpha } a complex number of absolute value 1 {\displaystyle 1} . The Koebe function and its rotations are schlicht: that is, univalent (analytic and one-to-one) and satisfying f ( 0 ) = 0 {\displaystyle f(0)=0} and f ′ ( 0 ) = 1 {\displaystyle f'(0)=1} .
Let
be univalent in | z | < 1 {\displaystyle |z|<1} . Then
This follows by applying Gronwall's area theorem to the odd univalent function
Equality holds if and only if g {\displaystyle g} is a rotated Koebe function.
This result was proved by Ludwig Bieberbach in 1916 and provided the basis for his celebrated conjecture that | a n | ≤ n {\displaystyle |a_{n}|\leq n} , proved in 1985 by Louis de Branges.
Applying an affine map, it can be assumed that
so that
In particular, the coefficient inequality gives that | a 2 | ≤ 2 {\displaystyle |a_{2}|\leq 2} . If w {\displaystyle w} is not in f ( D ) {\displaystyle f(\mathbf {D} )} , then
is univalent in | z | < 1 {\displaystyle |z|<1} .
Applying the coefficient inequality to h {\displaystyle h} gives
The Koebe distortion theorem gives a series of bounds for a univalent function and its derivative. It is a direct consequence of Bieberbach's inequality for the second coefficient and the Koebe quarter theorem.1
Let f ( z ) {\displaystyle f(z)} be a univalent function on | z | < 1 {\displaystyle |z|<1} normalized so that f ( 0 ) = 0 {\displaystyle f(0)=0} and f ′ ( 0 ) = 1 {\displaystyle f'(0)=1} and let r = | z | {\displaystyle r=|z|} . Then
with equality if and only if f {\displaystyle f} is a Koebe function
Pommerenke 1975, pp. 21–22 - Pommerenke, C. (1975), Univalent functions, with a chapter on quadratic differentials by Gerd Jensen, Studia Mathematica/Mathematische Lehrbücher, vol. 15, Vandenhoeck & Ruprecht ↩