Chirp mass

<h2 id="definition-from-component-masses">Definition from component masses</h2>
<p>A two-body system with component masses 
  
    
      
        
          m
          
            1
          
        
      
    
    {\displaystyle m_{1}}
  
 and 
  
    
      
        
          m
          
            2
          
        
      
    
    {\displaystyle m_{2}}
  
 has a chirp mass of
</p>

M
          
        
        =
        
          
            
              (
              
                m
                
                  1
                
              
              
                m
                
                  2
                
              
              
                )
                
                  3
                  
                    /
                  
                  5
                
              
            
            
              (
              
                m
                
                  1
                
              
              +
              
                m
                
                  2
                
              
              
                )
                
                  1
                  
                    /
                  
                  5
                
              
            
          
        
      
    
    {\displaystyle {\mathcal {M}}={\frac {(m_{1}m_{2})^{3/5}}{(m_{1}+m_{2})^{1/5}}}}
  
<a class="footnote-ref" id="fnref:1" href="#fn:1"><sup>1</sup></a><a class="footnote-ref" id="fnref:2" href="#fn:2"><sup>2</sup></a><a class="footnote-ref" id="fnref:3" href="#fn:3"><sup>3</sup></a>
<p>The chirp mass may also be expressed in terms of the total mass of the system 
  
    
      
        M
        =
        
          m
          
            1
          
        
        +
        
          m
          
            2
          
        
      
    
    {\displaystyle M=m_{1}+m_{2}}
  
 and other common mass parameters:
</p>
<ul><li>the <a href="/facts/Reduced_mass/GQgUNp8D">reduced mass</a> 
  
    
      
        μ
        =
        
          
            
              
                m
                
                  1
                
              
              
                m
                
                  2
                
              
            
            
              
                m
                
                  1
                
              
              +
              
                m
                
                  2
                
              
            
          
        
      
    
    {\displaystyle \mu ={\frac {m_{1}m_{2}}{m_{1}+m_{2}}}}
  
:

M
          
        
        =
        
          μ
          
            3
            
              /
            
            5
          
        
        
          M
          
            2
            
              /
            
            5
          
        
        ,
      
    
    {\displaystyle {\mathcal {M}}=\mu ^{3/5}M^{2/5},}
  
</li>
<li>the mass ratio 
  
    
      
        q
        =
        
          m
          
            1
          
        
        
          /
        
        
          m
          
            2
          
        
      
    
    {\displaystyle q=m_{1}/m_{2}}
  
:

M
          
        
        =
        
          
            [
            
              
                q
                
                  (
                  1
                  +
                  q
                  
                    )
                    
                      2
                    
                  
                
              
            
            ]
          
          
            3
            
              /
            
            5
          
        
        M
        ,
      
    
    {\displaystyle {\mathcal {M}}=\left[{\frac {q}{(1+q)^{2}}}\right]^{3/5}M,}
  
 or</li>
<li>the symmetric mass ratio 
  
    
      
        η
        =
        
          
            
              
                m
                
                  1
                
              
              
                m
                
                  2
                
              
            
            
              (
              
                m
                
                  1
                
              
              +
              
                m
                
                  2
                
              
              
                )
                
                  2
                
              
            
          
        
        =
        
          
            μ
            M
          
        
        =
        
          
            q
            
              (
              1
              +
              q
              
                )
                
                  2
                
              
            
          
        
        =
        
          
            (
            
              
                
                  m
                  
                    
                      g
                      e
                      o
                    
                  
                
                M
              
            
            )
          
          
            2
          
        
      
    
    {\displaystyle \eta ={\frac {m_{1}m_{2}}{(m_{1}+m_{2})^{2}}}={\frac {\mu }{M}}={\frac {q}{(1+q)^{2}}}=\left({\frac {m_{\rm {geo}}}{M}}\right)^{2}}
  
:

M
          
        
        =
        
          η
          
            3
            
              /
            
            5
          
        
        M
        .
      
    
    {\displaystyle {\mathcal {M}}=\eta ^{3/5}M.}

The symmetric mass ratio reaches its maximum value 
  
    
      
        η
        =
        
          
            1
            4
          
        
      
    
    {\displaystyle \eta ={\frac {1}{4}}}
  
 when 
  
    
      
        
          m
          
            1
          
        
        =
        
          m
          
            2
          
        
      
    
    {\displaystyle m_{1}=m_{2}}
  
, and thus 
  
    
      
        
          
            M
          
        
        =
        (
        1
        
          /
        
        4
        
          )
          
            3
            
              /
            
            5
          
        
        M
        ≈
        0.435
        
        M
        .
      
    
    {\displaystyle {\mathcal {M}}=(1/4)^{3/5}M\approx 0.435\,M.}
  
</li>
<li>the geometric mean of the component masses 
  
    
      
        
          m
          
            g
            e
            o
          
        
        =
        
          
            
              m
              
                1
              
            
            
              m
              
                2
              
            
          
        
      
    
    {\displaystyle m_{geo}={\sqrt {m_{1}m_{2}}}}
  
:

M
          
        
        =
        
          m
          
            
              g
              e
              o
            
          
        
        
          
            (
            
              
                
                  m
                  
                    
                      g
                      e
                      o
                    
                  
                
                M
              
            
            )
          
          
            1
            
              /
            
            5
          
        
        ,
      
    
    {\displaystyle {\mathcal {M}}=m_{\rm {geo}}\left({\frac {m_{\rm {geo}}}{M}}\right)^{1/5},}

If the two component masses are roughly similar, then the latter factor is close to 
  
    
      
        (
        1
        
          /
        
        2
        
          )
          
            1
            
              /
            
            5
          
        
        =
        0.871
        ,
      
    
    {\displaystyle (1/2)^{1/5}=0.871,}
  
 so 
  
    
      
        
          
            M
          
        
        ≈
        0.871
        
        
          m
          
            
              g
              e
              o
            
          
        
      
    
    {\displaystyle {\mathcal {M}}\approx 0.871\,m_{\rm {geo}}}
  
. This multiplier decreases for unequal component masses but quite slowly.  E.g. for a 3:1 mass ratio it becomes 
  
    
      
        
          
            M
          
        
        =
        0.846
        
        
          m
          
            
              g
              e
              o
            
          
        
      
    
    {\displaystyle {\mathcal {M}}=0.846\,m_{\rm {geo}}}
  
, while for a 10:1 mass ratio it is 
  
    
      
        
          
            M
          
        
        =
        0.779
        
        
          m
          
            
              g
              e
              o
            
          
        
        .
      
    
    {\displaystyle {\mathcal {M}}=0.779\,m_{\rm {geo}}.}
  
</li></ul>
<h2 id="orbital-evolution">Orbital evolution</h2>
<p>In <a href="/facts/General_relativity/jVsoIg8X">general relativity</a>, the phase evolution of a <a href="/facts/Two-body_problem_in_general_relativity/Djqr0I4L">binary orbit</a> can be computed using a <a href="/facts/Post-Newtonian_expansion/QxktcY1c">post-Newtonian expansion</a>, a perturbative expansion in powers of the orbital velocity 
  
    
      
        v
        
          /
        
        c
      
    
    {\displaystyle v/c}
  
.  The first order gravitational wave frequency, 
  
    
      
        f
      
    
    {\displaystyle f}
  
, evolution is described by the <a href="/facts/Differential_equation/9MGbE3Ca">differential equation</a>
</p>

d
              
              f
            
            
              
                d
              
              t
            
          
        
        =
        
          
            96
            5
          
        
        
          π
          
            8
            
              /
            
            3
          
        
        
          
            (
            
              
                
                  G
                  
                    
                      M
                    
                  
                
                
                  c
                  
                    3
                  
                
              
            
            )
          
          
            5
            
              /
            
            3
          
        
        
          f
          
            11
            
              /
            
            3
          
        
      
    
    {\displaystyle {\frac {\mathrm {d} f}{\mathrm {d} t}}={\frac {96}{5}}\pi ^{8/3}\left({\frac {G{\mathcal {M}}}{c^{3}}}\right)^{5/3}f^{11/3}}
  
,<a class="footnote-ref" id="fnref:4" href="#fn:4"><sup>4</sup></a>
<p>where 
  
    
      
        c
      
    
    {\displaystyle c}
  
 and 
  
    
      
        G
      
    
    {\displaystyle G}
  
 are the <a href="/facts/Speed_of_light/sKSQwdNx">speed of light</a> and <a href="/facts/Gravitational_constant/GdQ8tcBD">Newton's gravitational constant</a>, respectively.
</p><p>If one is able to measure both the frequency 
  
    
      
        f
      
    
    {\displaystyle f}
  
 and frequency derivative 
  
    
      
        
          
            
              f
              ˙
            
          
        
      
    
    {\displaystyle {\dot {f}}}
  
 of a gravitational wave signal, the chirp mass can be determined.[4][5]<a class="footnote-ref" id="fnref:5" href="#fn:5"><sup>5</sup></a>
</p>
<table><tbody><tr><td>                                          M                          =                                            c                              3                                      G                                                (                                                            5                  96                                                            π                                  −                  8                                      /                                    3                                                            f                                  −                  11                                      /                                    3                                                                                                  f                    ˙                                                                        )                                3                          /                        5                                {\displaystyle {\mathcal {M}}={\frac {c^{3}}{G}}\left({\frac {5}{96}}\pi ^{-8/3}f^{-11/3}{\dot {f}}\right)^{3/5}}  </td> <td></td> <td>1</td></tr></tbody></table>
<p>To disentangle the individual component masses in the system one must additionally measure higher order terms in the post-Newtonian expansion.<a class="footnote-ref" id="fnref:6" href="#fn:6"><sup>6</sup></a>
</p>
<h2 id="mass-redshift-degeneracy">Mass-redshift degeneracy</h2>
<p>One limitation of the chirp mass is that it is affected by <a href="/facts/Redshift/Qfl4VjDF">redshift</a>; what is actually derived from the observed gravitational waveform is the product
</p>

M
            
          
          
            o
          
        
        =
        
          
            M
          
        
        (
        1
        +
        z
        )
      
    
    {\displaystyle {\mathcal {M}}_{o}={\mathcal {M}}(1+z)}

<p>where 
  
    
      
        z
      
    
    {\displaystyle z}
  
 is the redshift.<a class="footnote-ref" id="fnref:7" href="#fn:7"><sup>7</sup></a><a class="footnote-ref" id="fnref:8" href="#fn:8"><sup>8</sup></a>  This redshifted chirp mass is larger<a class="footnote-ref" id="fnref:9" href="#fn:9"><sup>9</sup></a> than the source chirp mass, and can only be converted to a source chirp mass by finding the redshift 
  
    
      
        z
      
    
    {\displaystyle z}
  
.
</p><p>This is usually resolved by using the observed amplitude to find the chirp mass divided by distance, and solving both equations using <a href="/facts/Hubble%2527s_law/FJYfELCP">Hubble's law</a> to compute the relationship between distance and redshift.<a class="footnote-ref" id="fnref:10" href="#fn:10"><sup>10</sup></a>
</p><p>Xian Chen has pointed out that this assumes non-cosmological redshifts (<a href="/facts/Peculiar_velocity/88AJhmIQ">peculiar velocity</a> and <a href="/facts/Gravitational_redshift/cEFgB3Ns">gravitational redshift</a>) are negligible, and questions this assumption.<a class="footnote-ref" id="fnref:11" href="#fn:11"><sup>11</sup></a><a class="footnote-ref" id="fnref:12" href="#fn:12"><sup>12</sup></a>  If a binary pair of <a href="/facts/Stellar-mass_black_hole/8cz1uzAe">stellar-mass black holes</a> merge while closely orbiting a <a href="/facts/Supermassive_black_hole/BcuTx8Q5">supermassive black hole</a> (an <a href="/facts/Extreme_mass_ratio_inspiral/LCj5cmlo">extreme mass ratio inspiral</a>), the observed gravitational wave would experience significant gravitational and doppler redshift, leading to a falsely low redshift estimate, and therefore a falsely high mass.  He suggests that there are plausible reasons to suspect that the SMBH's <a href="/facts/Accretion_disc/8zJXshat">accretion disc</a> and <a href="/facts/Tidal_force/GJgxo7gp">tidal forces</a> would enhance the merger rate of black hole binaries near it, and the consequent falsely high mass estimates would explain the unexpectedly large masses of <a href="/facts/List_of_gravitational_wave_observations/PlWE2j7x">observed black hole mergers</a>.  (The question would be best resolved by a lower-frequency gravitational wave detector such as <a href="/facts/Laser_Interferometer_Space_Antenna/DAISKwem">LISA</a> which could observe the extreme mass ratio inspiral waveform.)
</p>
<h2 id="see-also">See also</h2>
<ul><li><a href="/facts/Reduced_mass/GQgUNp8D">Reduced mass</a></li>
<li><a href="/facts/Two-body_problem_in_general_relativity/Djqr0I4L">Two-body problem in general relativity</a></li></ul>
<h2 id="note">Note</h2>

<h2 id="references">References</h2>

<ol>
<li id="fn:1"><p>Cutler, Curt; Flanagan, Éanna E. (15 March 1994). "Gravitational waves from merging compact binaries: How accurately can one extract the binary's parameters from the inspiral waveform?". Physical Review D. 49 (6): 2658–2697. arXiv:gr-qc/9402014. Bibcode:1994PhRvD..49.2658C. doi:10.1103/PhysRevD.49.2658. PMID 10017261. S2CID 5808548. <a href="/wiki/ArXiv_(identifier)" target="_blank">/wiki/ArXiv_(identifier)</a> <a href="#fnref:1" class="footnote-back-ref">↩</a></p></li>
<li id="fn:2"><p>L. Blanchet; T. Damour; B. R. Iyer; C. M. Will; A. G. Wiseman (1 May 1995). "Gravitational-Radiation Damping of Compact Binary Systems to Second Post-Newtonian order". Phys. Rev. Lett. 74 (18): 3515–3518. arXiv:gr-qc/9501027. Bibcode:1995PhRvL..74.3515B. doi:10.1103/PhysRevLett.74.3515. PMID 10058225. S2CID 14265300. <a href="https://cds.cern.ch/record/275578" target="_blank">https://cds.cern.ch/record/275578</a> <a href="#fnref:2" class="footnote-back-ref">↩</a></p></li>
<li id="fn:3"><p>Blanchet, Luc; Iyerddag, Bala R.; Will, Clifford M.; Wiseman, Alan G. (April 1996). "Gravitational waveforms from inspiralling compact binaries to second-post-Newtonian order". Classical and Quantum Gravity. 13 (4): 575–584. arXiv:gr-qc/9602024. Bibcode:1996CQGra..13..575B. doi:10.1088/0264-9381/13/4/002. S2CID 14677428. <a href="/wiki/ArXiv_(identifier)" target="_blank">/wiki/ArXiv_(identifier)</a> <a href="#fnref:3" class="footnote-back-ref">↩</a></p></li>
<li id="fn:4"><p>Cutler, Curt; Flanagan, Éanna E. (15 March 1994). "Gravitational waves from merging compact binaries: How accurately can one extract the binary's parameters from the inspiral waveform?". Physical Review D. 49 (6): 2658–2697. arXiv:gr-qc/9402014. Bibcode:1994PhRvD..49.2658C. doi:10.1103/PhysRevD.49.2658. PMID 10017261. S2CID 5808548. <a href="/wiki/ArXiv_(identifier)" target="_blank">/wiki/ArXiv_(identifier)</a> <a href="#fnref:4" class="footnote-back-ref">↩</a></p></li>
<li id="fn:5"><p>Rewrite equation (1) to obtain the frequency evolution of gravitational waves from a coalescing binary:[6] 
                                                        f              ˙                                      =                              96            5                                    π                      8                          /                        3                                                (                                                            G                                                            M                                                                                        c                                      3                                                                        )                                5                          /                        3                                    f                      11                          /                        3                                {\displaystyle {\dot {f}}={\frac {96}{5}}\pi ^{8/3}\left({\frac {G{\mathcal {M}}}{c^{3}}}\right)^{5/3}f^{11/3}}    2
Integrating equation (2) with respect to time gives:[6]

96            5                                    π                      8                          /                        3                                                (                                                            G                                                            M                                                                                        c                                      3                                                                        )                                5                          /                        3                          t        +                              3            8                                    f                      −            8                          /                        3                          +        C        =        0              {\displaystyle {\frac {96}{5}}\pi ^{8/3}\left({\frac {G{\mathcal {M}}}{c^{3}}}\right)^{5/3}t+{\frac {3}{8}}f^{-8/3}+C=0}    3
where C is the constant of integration. Furthermore, on identifying 
  
    
      
        x
        ≡
        t
      
    
    {\displaystyle x\equiv t}
  
 and 
  
    
      
        y
        ≡
        
          
            3
            8
          
        
        
          f
          
            −
            8
            
              /
            
            3
          
        
      
    
    {\displaystyle y\equiv {\frac {3}{8}}f^{-8/3}}
  
, the chirp mass can be calculated from the slope of the line fitted through the data points (x, y).
 <a href="#fnref:5" class="footnote-back-ref">↩</a></p></li>
<li id="fn:6"><p>Cutler, Curt; Flanagan, Éanna E. (15 March 1994). "Gravitational waves from merging compact binaries: How accurately can one extract the binary's parameters from the inspiral waveform?". Physical Review D. 49 (6): 2658–2697. arXiv:gr-qc/9402014. Bibcode:1994PhRvD..49.2658C. doi:10.1103/PhysRevD.49.2658. PMID 10017261. S2CID 5808548. <a href="/wiki/ArXiv_(identifier)" target="_blank">/wiki/ArXiv_(identifier)</a> <a href="#fnref:6" class="footnote-back-ref">↩</a></p></li>
<li id="fn:7"><p>Schutz, Bernard F. (25 September 1986). "Determining the Hubble constant from gravitational wave observations". Nature. 323 (6086): 310–311. Bibcode:1986Natur.323..310S. doi:10.1038/323310a0. hdl:11858/00-001M-0000-0013-73C1-2. S2CID 4327285. <a href="/wiki/Bibcode_(identifier)" target="_blank">/wiki/Bibcode_(identifier)</a> <a href="#fnref:7" class="footnote-back-ref">↩</a></p></li>
<li id="fn:8"><p>Messenger, Chris; Takami, Kentaro; Gossan, Sarah; Rezzolla, Luciano; Sathyaprakash, B. S. (8 October 2014). "Source Redshifts from Gravitational-Wave Observations of Binary Neutron Star Mergers" (PDF). Physical Review X. 4 (4): 041004. arXiv:1312.1862. Bibcode:2014PhRvX...4d1004M. doi:10.1103/PhysRevX.4.041004. <a href="http://authors.library.caltech.edu/52424/1/PhysRevX.4.041004.pdf" target="_blank">http://authors.library.caltech.edu/52424/1/PhysRevX.4.041004.pdf</a> <a href="#fnref:8" class="footnote-back-ref">↩</a></p></li>
<li id="fn:9"><p>While it is not physically impossible to have 
  
    
      
        z
        <
        0
      
    
    {\displaystyle z<0}
  
, that would require orbiting massive objects which are moving toward the observer, something that is not observed in practice. <a href="#fnref:9" class="footnote-back-ref">↩</a></p></li>
<li id="fn:10"><p>Crudely, begin with a guess at the redshift, use that to compute the source chirp mass and source amplitude, divide by the observed amplitude to determine the distance, use Hubble's law to convert the distance to a redshift, and use that as an improved guess to repeat the process until sufficient accuracy is reached. <a href="#fnref:10" class="footnote-back-ref">↩</a></p></li>
<li id="fn:11"><p>Chen, Xian; Li, Shuo; Cao, Zhoujian (May 2019). "Mass-redshift degeneracy for the gravitational-wave sources in the vicinity of supermassive black holes". Monthly Notices of the Royal Astronomical Society. 485 (1): L141 – L145. arXiv:1703.10543. Bibcode:2019MNRAS.485L.141C. doi:10.1093/mnrasl/slz046. <a href="https://doi.org/10.1093%2Fmnrasl%2Fslz046" target="_blank">https://doi.org/10.1093%2Fmnrasl%2Fslz046</a> <a href="#fnref:11" class="footnote-back-ref">↩</a></p></li>
<li id="fn:12"><p>Chen, Xian (2021). "Distortion of Gravitational-Wave Signals by Astrophysical Environments". Handbook of Gravitational Wave Astronomy. pp. 1–22. arXiv:2009.07626. doi:10.1007/978-981-15-4702-7_39-1. ISBN 978-981-15-4702-7. S2CID 221739217. <a href="978-981-15-4702-7" target="_blank">978-981-15-4702-7</a> <a href="#fnref:12" class="footnote-back-ref">↩</a></p></li>
</ol>

Chirp mass open-in-new

Chirp mass