Let T {\displaystyle T} be a bounded linear operator acting on a Banach space X {\displaystyle X} over the complex scalar field C {\displaystyle \mathbb {C} } , and I {\displaystyle I} be the identity operator on X {\displaystyle X} . The spectrum of T {\displaystyle T} is the set of all λ ∈ C {\displaystyle \lambda \in \mathbb {C} } for which the operator T − λ I {\displaystyle T-\lambda I} does not have an inverse that is a bounded linear operator.
Since T − λ I {\displaystyle T-\lambda I} is a linear operator, the inverse is linear if it exists; and, by the bounded inverse theorem, it is bounded. Therefore, the spectrum consists precisely of those scalars λ {\displaystyle \lambda } for which T − λ I {\displaystyle T-\lambda I} is not bijective.
The spectrum of a given operator T {\displaystyle T} is often denoted σ ( T ) {\displaystyle \sigma (T)} , and its complement, the resolvent set, is denoted ρ ( T ) = C ∖ σ ( T ) {\displaystyle \rho (T)=\mathbb {C} \setminus \sigma (T)} . ( ρ ( T ) {\displaystyle \rho (T)} is sometimes used to denote the spectral radius of T {\displaystyle T} )
If λ {\displaystyle \lambda } is an eigenvalue of T {\displaystyle T} , then the operator T − λ I {\displaystyle T-\lambda I} is not one-to-one, and therefore its inverse ( T − λ I ) − 1 {\displaystyle (T-\lambda I)^{-1}} is not defined. However, the converse statement is not true: the operator T − λ I {\displaystyle T-\lambda I} may not have an inverse, even if λ {\displaystyle \lambda } is not an eigenvalue. Thus the spectrum of an operator always contains all its eigenvalues, but is not limited to them.
For example, consider the Hilbert space ℓ 2 ( Z ) {\displaystyle \ell ^{2}(\mathbb {Z} )} , that consists of all bi-infinite sequences of real numbers
that have a finite sum of squares ∑ i = − ∞ + ∞ v i 2 {\textstyle \sum _{i=-\infty }^{+\infty }v_{i}^{2}} . The bilateral shift operator T {\displaystyle T} simply displaces every element of the sequence by one position; namely if u = T ( v ) {\displaystyle u=T(v)} then u i = v i − 1 {\displaystyle u_{i}=v_{i-1}} for every integer i {\displaystyle i} . The eigenvalue equation T ( v ) = λ v {\displaystyle T(v)=\lambda v} has no nonzero solution in this space, since it implies that all the values v i {\displaystyle v_{i}} have the same absolute value (if | λ | = 1 {\displaystyle \vert \lambda \vert =1} ) or are a geometric progression (if | λ | ≠ 1 {\displaystyle \vert \lambda \vert \neq 1} ); either way, the sum of their squares would not be finite. However, the operator T − λ I {\displaystyle T-\lambda I} is not invertible if | λ | = 1 {\displaystyle |\lambda |=1} . For example, the sequence u {\displaystyle u} such that u i = 1 / ( | i | + 1 ) {\displaystyle u_{i}=1/(|i|+1)} is in ℓ 2 ( Z ) {\displaystyle \ell ^{2}(\mathbb {Z} )} ; but there is no sequence v {\displaystyle v} in ℓ 2 ( Z ) {\displaystyle \ell ^{2}(\mathbb {Z} )} such that ( T − I ) v = u {\displaystyle (T-I)v=u} (that is, v i − 1 = u i + v i {\displaystyle v_{i-1}=u_{i}+v_{i}} for all i {\displaystyle i} ).
The spectrum of a bounded operator T is always a closed, bounded subset of the complex plane.
If the spectrum were empty, then the resolvent function
would be defined everywhere on the complex plane and bounded. But it can be shown that the resolvent function R is holomorphic on its domain. By the vector-valued version of Liouville's theorem, this function is constant, thus everywhere zero as it is zero at infinity. This would be a contradiction.
The boundedness of the spectrum follows from the Neumann series expansion in λ; the spectrum σ(T) is bounded by ||T||. A similar result shows the closedness of the spectrum.
The bound ||T|| on the spectrum can be refined somewhat. The spectral radius, r(T), of T is the radius of the smallest circle in the complex plane which is centered at the origin and contains the spectrum σ(T) inside of it, i.e.
The spectral radius formula says2 that for any element T {\displaystyle T} of a Banach algebra,
One can extend the definition of spectrum to unbounded operators on a Banach space X. These operators are no longer elements in the Banach algebra B(X).
Let X be a Banach space and T : D ( T ) → X {\displaystyle T:\,D(T)\to X} be a linear operator defined on domain D ( T ) ⊆ X {\displaystyle D(T)\subseteq X} . A complex number λ is said to be in the resolvent set (also called regular set) of T {\displaystyle T} if the operator
has a bounded everywhere-defined inverse, i.e. if there exists a bounded operator
such that
A complex number λ is then in the spectrum if λ is not in the resolvent set.
For λ to be in the resolvent (i.e. not in the spectrum), just like in the bounded case, T − λ I {\displaystyle T-\lambda I} must be bijective, since it must have a two-sided inverse. As before, if an inverse exists, then its linearity is immediate, but in general it may not be bounded, so this condition must be checked separately.
By the closed graph theorem, boundedness of ( T − λ I ) − 1 {\displaystyle (T-\lambda I)^{-1}} does follow directly from its existence when T is closed. Then, just as in the bounded case, a complex number λ lies in the spectrum of a closed operator T if and only if T − λ I {\displaystyle T-\lambda I} is not bijective. Note that the class of closed operators includes all bounded operators.
The spectrum of an unbounded operator is in general a closed, possibly empty, subset of the complex plane. If the operator T is not closed, then σ ( T ) = C {\displaystyle \sigma (T)=\mathbb {C} } .
The following example indicates that non-closed operators may have empty spectra. Let T {\displaystyle T} denote the differentiation operator on L 2 ( [ 0 , 1 ] ) {\displaystyle L^{2}([0,1])} , whose domain is defined to be the closure of C c ∞ ( ( 0 , 1 ] ) {\displaystyle C_{c}^{\infty }((0,1])} with respect to the H 1 {\displaystyle H^{1}} -Sobolev space norm. This space can be characterized as all functions in H 1 ( [ 0 , 1 ] ) {\displaystyle H^{1}([0,1])} that are zero at t = 0 {\displaystyle t=0} . Then, T − z {\displaystyle T-z} has trivial kernel on this domain, as any H 1 ( [ 0 , 1 ] ) {\displaystyle H^{1}([0,1])} -function in its kernel is a constant multiple of e z t {\displaystyle e^{zt}} , which is zero at t = 0 {\displaystyle t=0} if and only if it is identically zero. Therefore, the complement of the spectrum is all of C . {\displaystyle \mathbb {C} .}
Further information: Decomposition of spectrum (functional analysis)
A bounded operator T on a Banach space is invertible, i.e. has a bounded inverse, if and only if T is bounded below, i.e. ‖ T x ‖ ≥ c ‖ x ‖ , {\displaystyle \|Tx\|\geq c\|x\|,} for some c > 0 , {\displaystyle c>0,} and has dense range. Accordingly, the spectrum of T can be divided into the following parts:
Note that the approximate point spectrum and residual spectrum are not necessarily disjoint3 (however, the point spectrum and the residual spectrum are).
The following subsections provide more details on the three parts of σ(T) sketched above.
If an operator is not injective (so there is some nonzero x with T(x) = 0), then it is clearly not invertible. So if λ is an eigenvalue of T, one necessarily has λ ∈ σ(T). The set of eigenvalues of T is also called the point spectrum of T, denoted by σp(T). Some authors refer to the closure of the point spectrum as the pure point spectrum σ p p ( T ) = σ p ( T ) ¯ {\displaystyle \sigma _{pp}(T)={\overline {\sigma _{p}(T)}}} while others simply consider σ p p ( T ) := σ p ( T ) . {\displaystyle \sigma _{pp}(T):=\sigma _{p}(T).} 45
More generally, by the bounded inverse theorem, T is not invertible if it is not bounded below; that is, if there is no c > 0 such that ||Tx|| ≥ c||x|| for all x ∈ X. So the spectrum includes the set of approximate eigenvalues, which are those λ such that T - λI is not bounded below; equivalently, it is the set of λ for which there is a sequence of unit vectors x1, x2, ... for which
The set of approximate eigenvalues is known as the approximate point spectrum, denoted by σ a p ( T ) {\displaystyle \sigma _{\mathrm {ap} }(T)} .
It is easy to see that the eigenvalues lie in the approximate point spectrum.
For example, consider the right shift R on l 2 ( Z ) {\displaystyle l^{2}(\mathbb {Z} )} defined by
where ( e j ) j ∈ N {\displaystyle {\big (}e_{j}{\big )}_{j\in \mathbb {N} }} is the standard orthonormal basis in l 2 ( Z ) {\displaystyle l^{2}(\mathbb {Z} )} . Direct calculation shows R has no eigenvalues, but every λ with | λ | = 1 {\displaystyle |\lambda |=1} is an approximate eigenvalue; letting xn be the vector
one can see that ||xn|| = 1 for all n, but
Since R is a unitary operator, its spectrum lies on the unit circle. Therefore, the approximate point spectrum of R is its entire spectrum.
This conclusion is also true for a more general class of operators. A unitary operator is normal. By the spectral theorem, a bounded operator on a Hilbert space H is normal if and only if it is equivalent (after identification of H with an L 2 {\displaystyle L^{2}} space) to a multiplication operator. It can be shown that the approximate point spectrum of a bounded multiplication operator equals its spectrum.
The discrete spectrum is defined as the set of normal eigenvalues or, equivalently, as the set of isolated points of the spectrum such that the corresponding Riesz projector is of finite rank. As such, the discrete spectrum is a strict subset of the point spectrum, i.e., σ d ( T ) ⊂ σ p ( T ) . {\displaystyle \sigma _{d}(T)\subset \sigma _{p}(T).}
The set of all λ for which T − λ I {\displaystyle T-\lambda I} is injective and has dense range, but is not surjective, is called the continuous spectrum of T, denoted by σ c ( T ) {\displaystyle \sigma _{\mathbb {c} }(T)} . The continuous spectrum therefore consists of those approximate eigenvalues which are not eigenvalues and do not lie in the residual spectrum. That is,
For example, A : l 2 ( N ) → l 2 ( N ) {\displaystyle A:\,l^{2}(\mathbb {N} )\to l^{2}(\mathbb {N} )} , e j ↦ e j / j {\displaystyle e_{j}\mapsto e_{j}/j} , j ∈ N {\displaystyle j\in \mathbb {N} } , is injective and has a dense range, yet R a n ( A ) ⊊ l 2 ( N ) {\displaystyle \mathrm {Ran} (A)\subsetneq l^{2}(\mathbb {N} )} . Indeed, if x = ∑ j ∈ N c j e j ∈ l 2 ( N ) {\textstyle x=\sum _{j\in \mathbb {N} }c_{j}e_{j}\in l^{2}(\mathbb {N} )} with c j ∈ C {\displaystyle c_{j}\in \mathbb {C} } such that ∑ j ∈ N | c j | 2 < ∞ {\textstyle \sum _{j\in \mathbb {N} }|c_{j}|^{2}<\infty } , one does not necessarily have ∑ j ∈ N | j c j | 2 < ∞ {\textstyle \sum _{j\in \mathbb {N} }\left|jc_{j}\right|^{2}<\infty } , and then ∑ j ∈ N j c j e j ∉ l 2 ( N ) {\textstyle \sum _{j\in \mathbb {N} }jc_{j}e_{j}\notin l^{2}(\mathbb {N} )} .
The set of λ ∈ C {\displaystyle \lambda \in \mathbb {C} } for which T − λ I {\displaystyle T-\lambda I} does not have dense range is known as the compression spectrum of T and is denoted by σ c p ( T ) {\displaystyle \sigma _{\mathrm {cp} }(T)} .
The set of λ ∈ C {\displaystyle \lambda \in \mathbb {C} } for which T − λ I {\displaystyle T-\lambda I} is injective but does not have dense range is known as the residual spectrum of T and is denoted by σ r ( T ) {\displaystyle \sigma _{\mathrm {r} }(T)} :
An operator may be injective, even bounded below, but still not invertible. The right shift on l 2 ( N ) {\displaystyle l^{2}(\mathbb {N} )} , R : l 2 ( N ) → l 2 ( N ) {\displaystyle R:\,l^{2}(\mathbb {N} )\to l^{2}(\mathbb {N} )} , R : e j ↦ e j + 1 , j ∈ N {\displaystyle R:\,e_{j}\mapsto e_{j+1},\,j\in \mathbb {N} } , is such an example. This shift operator is an isometry, therefore bounded below by 1. But it is not invertible as it is not surjective ( e 1 ∉ R a n ( R ) {\displaystyle e_{1}\not \in \mathrm {Ran} (R)} ), and moreover R a n ( R ) {\displaystyle \mathrm {Ran} (R)} is not dense in l 2 ( N ) {\displaystyle l^{2}(\mathbb {N} )} ( e 1 ∉ R a n ( R ) ¯ {\displaystyle e_{1}\notin {\overline {\mathrm {Ran} (R)}}} ).
The peripheral spectrum of an operator is defined as the set of points in its spectrum which have modulus equal to its spectral radius.6
There are five similar definitions of the essential spectrum of closed densely defined linear operator A : X → X {\displaystyle A:\,X\to X} which satisfy
All these spectra σ e s s , k ( A ) , 1 ≤ k ≤ 5 {\displaystyle \sigma _{\mathrm {ess} ,k}(A),\ 1\leq k\leq 5} , coincide in the case of self-adjoint operators.
The hydrogen atom provides an example of different types of the spectra. The hydrogen atom Hamiltonian operator H = − Δ − Z | x | {\displaystyle H=-\Delta -{\frac {Z}{|x|}}} , Z > 0 {\displaystyle Z>0} , with domain D ( H ) = H 1 ( R 3 ) {\displaystyle D(H)=H^{1}(\mathbb {R} ^{3})} has a discrete set of eigenvalues (the discrete spectrum σ d ( H ) {\displaystyle \sigma _{\mathrm {d} }(H)} , which in this case coincides with the point spectrum σ p ( H ) {\displaystyle \sigma _{\mathrm {p} }(H)} since there are no eigenvalues embedded into the continuous spectrum) that can be computed by the Rydberg formula. Their corresponding eigenfunctions are called eigenstates, or the bound states. The result of the ionization process is described by the continuous part of the spectrum (the energy of the collision/ionization is not "quantized"), represented by σ c o n t ( H ) = [ 0 , + ∞ ) {\displaystyle \sigma _{\mathrm {cont} }(H)=[0,+\infty )} (it also coincides with the essential spectrum, σ e s s ( H ) = [ 0 , + ∞ ) {\displaystyle \sigma _{\mathrm {ess} }(H)=[0,+\infty )} ).
Let X be a Banach space and T : X → X {\displaystyle T:\,X\to X} a closed linear operator with dense domain D ( T ) ⊂ X {\displaystyle D(T)\subset X} . If X* is the dual space of X, and T ∗ : X ∗ → X ∗ {\displaystyle T^{*}:\,X^{*}\to X^{*}} is the hermitian adjoint of T, then
Theorem—For a bounded (or, more generally, closed and densely defined) operator T,
In particular, σ r ( T ) ⊂ σ p ( T ∗ ) ¯ ⊂ σ r ( T ) ∪ σ p ( T ) {\displaystyle \sigma _{\mathrm {r} }(T)\subset {\overline {\sigma _{\mathrm {p} }(T^{*})}}\subset \sigma _{\mathrm {r} }(T)\cup \sigma _{\mathrm {p} }(T)} .
Suppose that R a n ( T − λ I ) {\displaystyle \mathrm {Ran} (T-\lambda I)} is not dense in X. By the Hahn–Banach theorem, there exists a non-zero φ ∈ X ∗ {\displaystyle \varphi \in X^{*}} that vanishes on R a n ( T − λ I ) {\displaystyle \mathrm {Ran} (T-\lambda I)} . For all x ∈ X,
Therefore, ( T ∗ − λ ¯ I ) φ = 0 ∈ X ∗ {\displaystyle (T^{*}-{\bar {\lambda }}I)\varphi =0\in X^{*}} and λ ¯ {\displaystyle {\bar {\lambda }}} is an eigenvalue of T*.
Conversely, suppose that λ ¯ {\displaystyle {\bar {\lambda }}} is an eigenvalue of T*. Then there exists a non-zero φ ∈ X ∗ {\displaystyle \varphi \in X^{*}} such that ( T ∗ − λ ¯ I ) φ = 0 {\displaystyle (T^{*}-{\bar {\lambda }}I)\varphi =0} , i.e.
If R a n ( T − λ I ) {\displaystyle \mathrm {Ran} (T-\lambda I)} is dense in X, then φ must be the zero functional, a contradiction. The claim is proved.
We also get σ p ( T ) ⊂ σ r ( T ∗ ) ∪ σ p ( T ∗ ) ¯ {\displaystyle \sigma _{\mathrm {p} }(T)\subset {\overline {\sigma _{\mathrm {r} }(T^{*})\cup \sigma _{\mathrm {p} }(T^{*})}}} by the following argument: X embeds isometrically into X**. Therefore, for every non-zero element in the kernel of T − λ I {\displaystyle T-\lambda I} there exists a non-zero element in X** which vanishes on R a n ( T ∗ − λ ¯ I ) {\displaystyle \mathrm {Ran} (T^{*}-{\bar {\lambda }}I)} . Thus R a n ( T ∗ − λ ¯ I ) {\displaystyle \mathrm {Ran} (T^{*}-{\bar {\lambda }}I)} can not be dense.
Furthermore, if X is reflexive, we have σ r ( T ∗ ) ¯ ⊂ σ p ( T ) {\displaystyle {\overline {\sigma _{\mathrm {r} }(T^{*})}}\subset \sigma _{\mathrm {p} }(T)} .
If T is a compact operator, or, more generally, an inessential operator, then it can be shown that the spectrum is countable, that zero is the only possible accumulation point, and that any nonzero λ in the spectrum is an eigenvalue.
A bounded operator A : X → X {\displaystyle A:\,X\to X} is quasinilpotent if ‖ A n ‖ 1 / n → 0 {\displaystyle \lVert A^{n}\rVert ^{1/n}\to 0} as n → ∞ {\displaystyle n\to \infty } (in other words, if the spectral radius of A equals zero). Such operators could equivalently be characterized by the condition
An example of such an operator is A : l 2 ( N ) → l 2 ( N ) {\displaystyle A:\,l^{2}(\mathbb {N} )\to l^{2}(\mathbb {N} )} , e j ↦ e j + 1 / 2 j {\displaystyle e_{j}\mapsto e_{j+1}/2^{j}} for j ∈ N {\displaystyle j\in \mathbb {N} } .
If X is a Hilbert space and T is a self-adjoint operator (or, more generally, a normal operator), then a remarkable result known as the spectral theorem gives an analogue of the diagonalisation theorem for normal finite-dimensional operators (Hermitian matrices, for example).
For self-adjoint operators, one can use spectral measures to define a decomposition of the spectrum into absolutely continuous, pure point, and singular parts.
The definitions of the resolvent and spectrum can be extended to any continuous linear operator T {\displaystyle T} acting on a Banach space X {\displaystyle X} over the real field R {\displaystyle \mathbb {R} } (instead of the complex field C {\displaystyle \mathbb {C} } ) via its complexification T C {\displaystyle T_{\mathbb {C} }} . In this case we define the resolvent set ρ ( T ) {\displaystyle \rho (T)} as the set of all λ ∈ C {\displaystyle \lambda \in \mathbb {C} } such that T C − λ I {\displaystyle T_{\mathbb {C} }-\lambda I} is invertible as an operator acting on the complexified space X C {\displaystyle X_{\mathbb {C} }} ; then we define σ ( T ) = C ∖ ρ ( T ) {\displaystyle \sigma (T)=\mathbb {C} \setminus \rho (T)} .
The real spectrum of a continuous linear operator T {\displaystyle T} acting on a real Banach space X {\displaystyle X} , denoted σ R ( T ) {\displaystyle \sigma _{\mathbb {R} }(T)} , is defined as the set of all λ ∈ R {\displaystyle \lambda \in \mathbb {R} } for which T − λ I {\displaystyle T-\lambda I} fails to be invertible in the real algebra of bounded linear operators acting on X {\displaystyle X} . In this case we have σ ( T ) ∩ R = σ R ( T ) {\displaystyle \sigma (T)\cap \mathbb {R} =\sigma _{\mathbb {R} }(T)} . Note that the real spectrum may or may not coincide with the complex spectrum. In particular, the real spectrum could be empty.
Let B be a complex Banach algebra containing a unit e. Then we define the spectrum σ(x) (or more explicitly σB(x)) of an element x of B to be the set of those complex numbers λ for which λe − x is not invertible in B. This extends the definition for bounded linear operators B(X) on a Banach space X, since B(X) is a unital Banach algebra.
Kreyszig, Erwin. Introductory Functional Analysis with Applications. ↩
Theorem 3.3.3 of Kadison & Ringrose, 1983, Fundamentals of the Theory of Operator Algebras, Vol. I: Elementary Theory, New York: Academic Press, Inc. ↩
"Nonempty intersection between approximate point spectrum and residual spectrum". https://math.stackexchange.com/questions/1613668/nonempty-intersection-between-approximate-point-spectrum-and-residual-spectrum ↩
Teschl 2014, p. 115. - Teschl, G. (2014). Mathematical Methods in Quantum Mechanics. Providence (R.I): American Mathematical Soc. ISBN 978-1-4704-1704-8. ↩
Simon 2005, p. 44. - Simon, Barry (2005). Orthogonal polynomials on the unit circle. Part 1. Classical theory. American Mathematical Society Colloquium Publications. Vol. 54. Providence, R.I.: American Mathematical Society. ISBN 978-0-8218-3446-6. MR 2105088. https://mathscinet.ams.org/mathscinet-getitem?mr=2105088 ↩
Zaanen, Adriaan C. (2012). Introduction to Operator Theory in Riesz Spaces. Springer Science & Business Media. p. 304. ISBN 9783642606373. Retrieved 8 September 2017. 9783642606373 ↩