If A {\displaystyle A} admits a totally ordered cofinal subset, then we can find a subset B {\displaystyle B} that is well-ordered and cofinal in A . {\displaystyle A.} Any subset of B {\displaystyle B} is also well-ordered. Two cofinal subsets of B {\displaystyle B} with minimal cardinality (that is, their cardinality is the cofinality of B {\displaystyle B} ) need not be order isomorphic (for example if B = ω + ω , {\displaystyle B=\omega +\omega ,} then both ω + ω {\displaystyle \omega +\omega } and { ω + n : n < ω } {\displaystyle \{\omega +n:n<\omega \}} viewed as subsets of B {\displaystyle B} have the countable cardinality of the cofinality of B {\displaystyle B} but are not order isomorphic). But cofinal subsets of B {\displaystyle B} with minimal order type will be order isomorphic.
The cofinality of an ordinal α {\displaystyle \alpha } is the smallest ordinal δ {\displaystyle \delta } that is the order type of a cofinal subset of α . {\displaystyle \alpha .} The cofinality of a set of ordinals or any other well-ordered set is the cofinality of the order type of that set.
Thus for a limit ordinal α , {\displaystyle \alpha ,} there exists a δ {\displaystyle \delta } -indexed strictly increasing sequence with limit α . {\displaystyle \alpha .} For example, the cofinality of ω 2 {\displaystyle \omega ^{2}} is ω , {\displaystyle \omega ,} because the sequence ω ⋅ m {\displaystyle \omega \cdot m} (where m {\displaystyle m} ranges over the natural numbers) tends to ω 2 ; {\displaystyle \omega ^{2};} but, more generally, any countable limit ordinal has cofinality ω . {\displaystyle \omega .} An uncountable limit ordinal may have either cofinality ω {\displaystyle \omega } as does ω ω {\displaystyle \omega _{\omega }} or an uncountable cofinality.
The cofinality of 0 is 0. The cofinality of any successor ordinal is 1. The cofinality of any nonzero limit ordinal is an infinite regular cardinal.
Main article: Regular cardinal
A regular ordinal is an ordinal that is equal to its cofinality. A singular ordinal is any ordinal that is not regular.
Every regular ordinal is the initial ordinal of a cardinal. Any limit of regular ordinals is a limit of initial ordinals and thus is also initial but need not be regular. Assuming the axiom of choice, ω α + 1 {\displaystyle \omega _{\alpha +1}} is regular for each α . {\displaystyle \alpha .} In this case, the ordinals 0 , 1 , ω , ω 1 , {\displaystyle 0,1,\omega ,\omega _{1},} and ω 2 {\displaystyle \omega _{2}} are regular, whereas 2 , 3 , ω ω , {\displaystyle 2,3,\omega _{\omega },} and ω ω ⋅ 2 {\displaystyle \omega _{\omega \cdot 2}} are initial ordinals that are not regular.
The cofinality of any ordinal α {\displaystyle \alpha } is a regular ordinal, that is, the cofinality of the cofinality of α {\displaystyle \alpha } is the same as the cofinality of α . {\displaystyle \alpha .} So the cofinality operation is idempotent.
If κ {\displaystyle \kappa } is an infinite cardinal number, then cf ( κ ) {\displaystyle \operatorname {cf} (\kappa )} is the least cardinal such that there is an unbounded function from cf ( κ ) {\displaystyle \operatorname {cf} (\kappa )} to κ ; {\displaystyle \kappa ;} cf ( κ ) {\displaystyle \operatorname {cf} (\kappa )} is also the cardinality of the smallest set of strictly smaller cardinals whose sum is κ ; {\displaystyle \kappa ;} more precisely cf ( κ ) = min { | I | : κ = ∑ i ∈ I λ i ∧ ∀ i ∈ I : λ i < κ } . {\displaystyle \operatorname {cf} (\kappa )=\min \left\{|I|\ :\ \kappa =\sum _{i\in I}\lambda _{i}\ \land \forall i\in I\colon \lambda _{i}<\kappa \right\}.}
That the set above is nonempty comes from the fact that κ = ⋃ i ∈ κ { i } {\displaystyle \kappa =\bigcup _{i\in \kappa }\{i\}} that is, the disjoint union of κ {\displaystyle \kappa } singleton sets. This implies immediately that cf ( κ ) ≤ κ . {\displaystyle \operatorname {cf} (\kappa )\leq \kappa .} The cofinality of any totally ordered set is regular, so cf ( κ ) = cf ( cf ( κ ) ) . {\displaystyle \operatorname {cf} (\kappa )=\operatorname {cf} (\operatorname {cf} (\kappa )).}
Using König's theorem, one can prove κ < κ cf ( κ ) {\displaystyle \kappa <\kappa ^{\operatorname {cf} (\kappa )}} and κ < cf ( 2 κ ) {\displaystyle \kappa <\operatorname {cf} \left(2^{\kappa }\right)} for any infinite cardinal κ . {\displaystyle \kappa .}
The last inequality implies that the cofinality of the cardinality of the continuum must be uncountable. On the other hand, ℵ ω = ⋃ n < ω ℵ n , {\displaystyle \aleph _{\omega }=\bigcup _{n<\omega }\aleph _{n},} the ordinal number ω being the first infinite ordinal, so that the cofinality of ℵ ω {\displaystyle \aleph _{\omega }} is card(ω) = ℵ 0 . {\displaystyle \aleph _{0}.} (In particular, ℵ ω {\displaystyle \aleph _{\omega }} is singular.) Therefore, 2 ℵ 0 ≠ ℵ ω . {\displaystyle 2^{\aleph _{0}}\neq \aleph _{\omega }.}
(Compare to the continuum hypothesis, which states 2 ℵ 0 = ℵ 1 . {\displaystyle 2^{\aleph _{0}}=\aleph _{1}.} )
Generalizing this argument, one can prove that for a limit ordinal δ {\displaystyle \delta } cf ( ℵ δ ) = cf ( δ ) . {\displaystyle \operatorname {cf} (\aleph _{\delta })=\operatorname {cf} (\delta ).}
On the other hand, if the axiom of choice holds, then for a successor or zero ordinal δ {\displaystyle \delta } cf ( ℵ δ ) = ℵ δ . {\displaystyle \operatorname {cf} (\aleph _{\delta })=\aleph _{\delta }.}
Shelah, Saharon (26 November 2002). "Logical Dreams". arXiv:math/0211398. /wiki/ArXiv_(identifier) ↩