We want the dimension of a point to be 0, and a point has empty boundary, so we start with
Then inductively, ind(X) is the smallest n such that, for every x ∈ X {\displaystyle x\in X} and every open set U containing x, there is an open set V containing x, such that the closure of V is a subset of U, and the boundary of V has small inductive dimension less than or equal to n − 1. (If X is a Euclidean n-dimensional space, V can be chosen to be an n-dimensional ball centered at x.)
For the large inductive dimension, we restrict the choice of V still further; Ind(X) is the smallest n such that, for every closed subset F of every open subset U of X, there is an open V in between (that is, F is a subset of V and the closure of V is a subset of U), such that the boundary of V has large inductive dimension less than or equal to n − 1.1
Let dim {\displaystyle \dim } be the Lebesgue covering dimension. For any topological space X, we have
Urysohn's theorem states that when X is a normal space with a countable base, then
Such spaces are exactly the separable and metrizable X (see Urysohn's metrization theorem).
The Nöbeling–Pontryagin theorem then states that such spaces with finite dimension are characterised up to homeomorphism as the subspaces of the Euclidean spaces, with their usual topology. The Menger–Nöbeling theorem (1932) states that if X {\displaystyle X} is compact metric separable and of dimension n {\displaystyle n} , then it embeds as a subspace of Euclidean space of dimension 2 n + 1 {\displaystyle 2n+1} . (Georg Nöbeling was a student of Karl Menger. He introduced Nöbeling space, the subspace of R 2 n + 1 {\displaystyle \mathbf {R} ^{2n+1}} consisting of points with at least n + 1 {\displaystyle n+1} co-ordinates being irrational numbers, which has universal properties for embedding spaces of dimension n {\displaystyle n} .)
Assuming only X metrizable we have (Miroslav Katětov)
or assuming X compact and Hausdorff (P. S. Aleksandrov)
Either inequality here may be strict; an example of Vladimir V. Filippov shows that the two inductive dimensions may differ.
A separable metric space X satisfies the inequality Ind X ≤ n {\displaystyle \operatorname {Ind} X\leq n} if and only if for every closed sub-space A {\displaystyle A} of the space X {\displaystyle X} and each continuous mapping f : A → S n {\displaystyle f:A\to S^{n}} there exists a continuous extension f ¯ : X → S n {\displaystyle {\bar {f}}:X\to S^{n}} .
Arkhangelskii, A.V.; Pontryagin, L.S. (1990). General Topology. Vol. I. Berlin, DE: Springer-Verlag. ISBN 3-540-18178-4. Page 104 3-540-18178-4 ↩