Napoleon points

<h2 id="definition-of-the-points">Definition of the points</h2>
<h3>First Napoleon point</h3>

Let △ABC be any given <a href="/facts/Plane_(geometry)/tAUtRFcn">plane</a> <a href="/facts/Triangle/cRXUwsMn">triangle</a>. On the sides BC, CA, AB of the triangle, construct outwardly drawn <a href="/facts/Equilateral_triangle/MJomsYDS">equilateral triangles</a> △DBC, △ECA, △FAB respectively. Let the <a href="/facts/Centroid/H6dDbg0h">centroids</a> of these triangles be X, Y, Z respectively. Then the lines AX, BY, CZ are <a href="/facts/Concurrent_lines/zPT6S4w9">concurrent</a>. The point of concurrence N1 is the first Napoleon point, or the outer Napoleon point, of the triangle △ABC.
The triangle △XYZ is called the outer Napoleon triangle of △ABC. <a href="/facts/Napoleon%27s_theorem/KgIHkTQu">Napoleon's theorem</a> asserts that this triangle is an <a href="/facts/Equilateral_triangle/MJomsYDS">equilateral triangle</a>.
In <a href="/facts/Clark_Kimberling/WMRRw662">Clark Kimberling</a>'s <a href="/facts/Encyclopedia_of_Triangle_Centers/ClS9kJor">Encyclopedia of Triangle Centers</a>, the first Napoleon point is denoted by X(17).<a class="footnote-ref" id="fnref:3" href="#fn:3">3</a>

<ul><li>The <a href="/facts/Trilinear_coordinates/PLCFluMm">trilinear coordinates</a> of N1:
 
 
 
 
 
 
 
 
 csc
 ⁡
 (
 A
 +
 
 
 
 π
 6
 
 
 
 )
 :
 csc
 ⁡
 (
 B
 +
 
 
 
 π
 6
 
 
 
 )
 :
 csc
 ⁡
 (
 C
 +
 
 
 
 π
 6
 
 
 
 )
 
 
 
 
 =
  
 
 
 sec
 ⁡
 (
 A
 −
 
 
 
 π
 3
 
 
 
 )
 :
 sec
 ⁡
 (
 B
 −
 
 
 
 π
 3
 
 
 
 )
 :
 sec
 ⁡
 (
 C
 −
 
 
 
 π
 3
 
 
 
 )
 
 
 
 
 
 
 {\displaystyle {\begin{aligned}&\csc(A+{\tfrac {\pi }{6}}):\csc(B+{\tfrac {\pi }{6}}):\csc(C+{\tfrac {\pi }{6}})\\[2pt]=\ &\sec(A-{\tfrac {\pi }{3}}):\sec(B-{\tfrac {\pi }{3}}):\sec(C-{\tfrac {\pi }{3}})\end{aligned}}}
 
</li>
<li>The <a href="/facts/Barycentric_coordinate_system_(mathematics)/ymlRaudU">barycentric coordinates</a> of N1:
 
 
 
 a
 csc
 ⁡
 (
 A
 +
 
 
 
 π
 6
 
 
 
 )
 :
 b
 csc
 ⁡
 (
 B
 +
 
 
 
 π
 6
 
 
 
 )
 :
 c
 csc
 ⁡
 (
 C
 +
 
 
 
 π
 6
 
 
 
 )
 
 
 {\displaystyle a\csc(A+{\tfrac {\pi }{6}}):b\csc(B+{\tfrac {\pi }{6}}):c\csc(C+{\tfrac {\pi }{6}})}
 
</li></ul>
<h3>Second Napoleon point</h3>

Let △ABC be any given <a href="/facts/Plane_(geometry)/tAUtRFcn">plane</a> <a href="/facts/Triangle/cRXUwsMn">triangle</a>. On the sides BC, CA, AB of the triangle, construct inwardly drawn equilateral triangles △DBC, △ECA, △FAB respectively. Let the <a href="/facts/Centroid/H6dDbg0h">centroids</a> of these triangles be X, Y, Z respectively. Then the lines AX, BY, CZ are concurrent. The point of concurrence N2 is the second Napoleon point, or the inner Napoleon point, of △ABC.
The triangle △XYZ is called the inner Napoleon triangle of △ABC. <a href="/facts/Napoleon%27s_theorem/KgIHkTQu">Napoleon's theorem</a> asserts that this triangle is an equilateral triangle.
In Clark Kimberling's Encyclopedia of Triangle Centers, the second Napoleon point is denoted by X(18).<a class="footnote-ref" id="fnref:4" href="#fn:4">4</a>

<ul><li>The trilinear coordinates of N2:
 
 
 
 
 
 
 
 
 csc
 ⁡
 (
 A
 −
 
 
 
 π
 6
 
 
 
 )
 :
 csc
 ⁡
 (
 B
 −
 
 
 
 π
 6
 
 
 
 )
 :
 csc
 ⁡
 (
 C
 −
 
 
 
 π
 6
 
 
 
 )
 
 
 
 
 =
  
 
 
 sec
 ⁡
 (
 A
 +
 
 
 
 π
 3
 
 
 
 )
 :
 sec
 ⁡
 (
 B
 +
 
 
 
 π
 3
 
 
 
 )
 :
 sec
 ⁡
 (
 C
 +
 
 
 
 π
 3
 
 
 
 )
 
 
 
 
 
 
 {\displaystyle {\begin{aligned}&\csc(A-{\tfrac {\pi }{6}}):\csc(B-{\tfrac {\pi }{6}}):\csc(C-{\tfrac {\pi }{6}})\\[2pt]=\ &\sec(A+{\tfrac {\pi }{3}}):\sec(B+{\tfrac {\pi }{3}}):\sec(C+{\tfrac {\pi }{3}})\end{aligned}}}
 
</li>
<li>The barycentric coordinates of N2:
 
 
 
 a
 csc
 ⁡
 (
 A
 −
 
 
 
 π
 6
 
 
 
 )
 :
 b
 csc
 ⁡
 (
 B
 −
 
 
 
 π
 6
 
 
 
 )
 :
 c
 csc
 ⁡
 (
 C
 −
 
 
 
 π
 6
 
 
 
 )
 
 
 {\displaystyle a\csc(A-{\tfrac {\pi }{6}}):b\csc(B-{\tfrac {\pi }{6}}):c\csc(C-{\tfrac {\pi }{6}})}
 
</li></ul>
Two points closely related to the Napoleon points are the <a href="/facts/Fermat_point/QRvKxfE6">Fermat-Torricelli points</a> (ETC's X(13) and X(14)). If instead of constructing lines joining the equilateral triangles' centroids to the respective vertices one now constructs lines joining the equilateral triangles' apices to the respective vertices of the triangle, the three lines so constructed are again concurrent. The points of concurrence are called the Fermat-Torricelli points, sometimes denoted F1 and F2. The intersection of the Fermat line (i.e., that line joining the two Fermat-Torricelli points) and the Napoleon line (i.e., that line joining the two Napoleon points) is the triangle's <a href="/facts/Symmedian/CVeo0k45">symmedian point</a> (ETC's X(6)).

<h2 id="generalizations">Generalizations</h2>
The results regarding the existence of the Napoleon points can be <a href="/facts/Generalization/v0b1pwUx">generalized</a> in different ways. In defining the Napoleon points we begin with equilateral triangles drawn on the sides of △ABC and then consider the centers X, Y, Z of these triangles. These centers can be thought as the vertices of <a href="/facts/Isosceles_triangle/rvLe3yqK">isosceles triangles</a> erected on the sides of triangle ABC with the base angles equal to π/6 (30 degrees). The generalizations seek to determine other triangles that, when erected over the sides of △ABC, have concurrent lines joining their external vertices and the vertices of △ABC.

<h3>Isosceles triangles</h3>

This generalization asserts the following:<a class="footnote-ref" id="fnref:5" href="#fn:5">5</a>

If the three triangles △XBC, △YCA, △ZAB, constructed on the sides of the given triangle △ABC as bases, are <a href="/facts/Similar_triangle/Sbd6hEAN">similar</a>, <a href="/facts/Isosceles_triangle/rvLe3yqK">isosceles</a> and similarly situated, then the lines AX, BY, CZ concur at a point N.
If the common base angle is θ, then the vertices of the three triangles have the following trilinear coordinates.

X
                =
              
              
                −
                sin
                ⁡
                θ
              
              
                :
              
              
                sin
                ⁡
                (
                C
                +
                θ
                )
              
              
                :
              
              
                sin
                ⁡
                (
                B
                +
                θ
                )
              
            
            
              
                Y
                =
              
              
                sin
                ⁡
                (
                C
                +
                θ
                )
              
              
                :
              
              
                −
                sin
                ⁡
                θ
              
              
                :
              
              
                sin
                ⁡
                (
                A
                +
                θ
                )
              
            
            
              
                Z
                =
              
              
                sin
                ⁡
                (
                B
                +
                θ
                )
              
              
                :
              
              
                sin
                ⁡
                (
                A
                +
                θ
                )
              
              
                :
              
              
                −
                sin
                ⁡
                θ
              
            
          
        
      
    
    {\displaystyle {\begin{array}{rccccc}X=&-\sin \theta &:&\sin(C+\theta )&:&\sin(B+\theta )\\Y=&\sin(C+\theta )&:&-\sin \theta &:&\sin(A+\theta )\\Z=&\sin(B+\theta )&:&\sin(A+\theta )&:&-\sin \theta \end{array}}}

The trilinear coordinates of N are

csc
        ⁡
        (
        A
        +
        θ
        )
        :
        csc
        ⁡
        (
        B
        +
        θ
        )
        :
        csc
        ⁡
        (
        C
        +
        θ
        )
      
    
    {\displaystyle \csc(A+\theta ):\csc(B+\theta ):\csc(C+\theta )}

A few special cases are interesting.

<table><tbody><tr><th>Value of θ</th><th>The point N</th></tr><tr><td>⁠ 0 {\displaystyle 0} ⁠</td><td>G, the centroid of △ABC</td></tr><tr><td>⁠ π 2 , − π 2 {\displaystyle {\frac {\pi }{2}},-{\frac {\pi }{2}}} ⁠</td><td>O, the orthocenter of △ABC</td></tr><tr><td>⁠ π 4 , − π 4 {\displaystyle {\frac {\pi }{4}},-{\frac {\pi }{4}}} ⁠</td><td>The <a href="/facts/Vecten_points/GA7vVJoK">Vecten points</a></td></tr><tr><td>⁠ π 6 {\displaystyle {\frac {\pi }{6}}} ⁠</td><td>N1, the first Napoleon point X(17)</td></tr><tr><td>⁠ − π 6 {\displaystyle -{\frac {\pi }{6}}} ⁠</td><td>N2, the second Napoleon point X(18)</td></tr><tr><td>⁠ π 3 {\displaystyle {\frac {\pi }{3}}} ⁠</td><td>F1, the <a href="/facts/Fermat_point/QRvKxfE6">first Fermat–Torricelli point X(13)</a></td></tr><tr><td>⁠ − π 3 {\displaystyle -{\frac {\pi }{3}}} ⁠</td><td>F2, the second Fermat–Torricelli point X(14)</td></tr><tr><td> { − A if  A < π / 2 π − A if  A > π / 2 {\displaystyle {\begin{cases}-A&{\text{if }}A<\pi /2\\\pi -A&{\text{if }}A>\pi /2\end{cases}}} </td><td>The vertex A</td></tr><tr><td> { − B if  B < π / 2 π − B if  B > π / 2 {\displaystyle {\begin{cases}-B&{\text{if }}B<\pi /2\\\pi -B&{\text{if }}B>\pi /2\end{cases}}} </td><td>The vertex B</td></tr><tr><td> { − C if  C < π / 2 π − C if  C > π / 2 {\displaystyle {\begin{cases}-C&{\text{if }}C<\pi /2\\\pi -C&{\text{if }}C>\pi /2\end{cases}}} </td><td>The vertex C</td></tr></tbody></table>
Moreover, the <a href="/facts/Locus_(mathematics)/t4swdGJq">locus</a> of N as the base angle θ varies between −π/2 and π/2 is the <a href="/facts/Conic/teqgLptX">conic</a>

 
 
 
 
 
 
 sin
 ⁡
 (
 B
 −
 C
 )
 
 x
 
 
 +
 
 
 
 sin
 ⁡
 (
 C
 −
 A
 )
 
 y
 
 
 +
 
 
 
 sin
 ⁡
 (
 A
 −
 B
 )
 
 z
 
 
 =
 0.
 
 
 {\displaystyle {\frac {\sin(B-C)}{x}}+{\frac {\sin(C-A)}{y}}+{\frac {\sin(A-B)}{z}}=0.}

This <a href="/facts/Conic/teqgLptX">conic</a> is a <a href="/facts/Rectangular_hyperbola/6R6ER0mY">rectangular hyperbola</a> and it is called the <a href="/facts/Kiepert_conics/ew4f1pVW">Kiepert hyperbola</a> in honor of <a href="/facts/Ludwig_Kiepert/c8F1osnM">Ludwig Kiepert</a> (1846–1934), the mathematician who discovered this result.<a class="footnote-ref" id="fnref:6" href="#fn:6">6</a> This hyperbola is the unique conic which passes through the five points A, B, C, G, O.

<h3>Similar triangles</h3>

The three triangles △XBC, △YCA, △ZAB erected over the sides of the triangle △ABC need not be isosceles for the three lines AX, BY, CZ to be concurrent.<a class="footnote-ref" id="fnref:7" href="#fn:7">7</a>

If similar triangles △XBC, △AYC, △ABZ are constructed outwardly on the sides of any triangle △ABC then the lines AX, BY, CZ are concurrent.
<h3>Arbitrary triangles</h3>
The concurrence of the lines AX, BY, CZ holds even in much relaxed conditions. The following result states one of the most general conditions for the lines AX, BY, CZ to be concurrent.<a class="footnote-ref" id="fnref:8" href="#fn:8">8</a>

If triangles △XBC, △YCA, △ZAB are constructed outwardly on the sides of any triangle △ABC such that

 
 
 
 ∠
 C
 B
 X
 =
 ∠
 A
 B
 Z
 ,
 
 ∠
 A
 C
 Y
 =
 ∠
 B
 C
 X
 ,
 
 ∠
 B
 A
 Z
 =
 ∠
 C
 A
 Y
 ;
 
 
 {\displaystyle \angle CBX=\angle ABZ,\quad \angle ACY=\angle BCX,\quad \angle BAZ=\angle CAY;}

then the lines AX, BY, CZ are concurrent.
The point of concurrency is known as the <a href="/facts/Jacobi_point/0cpe0lK4">Jacobi point</a>.

<h2 id="history">History</h2>
Coxeter and Greitzer state the Napoleon Theorem thus: If equilateral triangles are erected externally on the sides of any triangle, their centers form an equilateral triangle. They observe that Napoleon Bonaparte was a bit of a mathematician with a great interest in geometry. However, they doubt whether Napoleon knew enough geometry to discover the theorem attributed to him.<a class="footnote-ref" id="fnref:9" href="#fn:9">9</a>
The earliest recorded appearance of the result embodied in Napoleon's theorem is in an article in <a href="/facts/The_Ladies%27_Diary/A8JGHQgX">The Ladies' Diary</a> appeared in 1825. The Ladies' Diary was an annual periodical which was in circulation in London from 1704 to 1841. The result appeared as part of a question posed by W. Rutherford, Woodburn.

VII. Quest.(1439); by Mr. W. Rutherford, Woodburn." Describe equilateral triangles (the vertices being either all outward or all inward) upon the three sides of any triangle ABC: then the lines which join the centers of gravity of those three equilateral triangles will constitute an equilateral triangle. Required a demonstration."
However, there is no reference to the existence of the so-called Napoleon points in this question. <a href="/facts/Christoph_J._Scriba/eTvmQChM">Christoph J. Scriba</a>, a German <a href="/facts/Historian_of_mathematics/18h5rQA5">historian of mathematics</a>, has studied the problem of attributing the Napoleon points to <a href="/facts/Napoleon/8TKBIjPM">Napoleon</a> in a paper in <a href="/facts/Historia_Mathematica/cH72CmHe">Historia Mathematica</a>.<a class="footnote-ref" id="fnref:10" href="#fn:10">10</a>

<h2 id="see-also">See also</h2>

<ul><li><a href="/facts/Triangle_center/FKfm090E">Triangle center</a></li>
<li><a href="/facts/Triangle_conic/hBX4wxAu">Triangle conic</a></li>
<li><a href="/facts/Napoleon%27s_theorem/KgIHkTQu">Napoleon's theorem</a></li>
<li><a href="/facts/Napoleon%27s_problem/lukH1KSr">Napoleon's problem</a></li>
<li><a href="/facts/Van_Aubel%27s_theorem/LL5Nc4x9">Van Aubel's theorem</a></li>
<li><a href="/facts/Fermat_point/QRvKxfE6">Fermat point</a></li></ul>

<h2 id="further-reading">Further reading</h2>
<ul><li>Stachel, Hellmuth (2002). <a href="http://www.emis.de/journals/BAG/vol.43/no.2/b43h2sta.pdf">"Napoleon's Theorem and Generalizations Through Linear Maps"</a> (PDF). Contributions to Algebra and Geometry. 43 (2): 433–444. Retrieved 25 April 2012.</li>
<li>Grünbaum, Branko (2001). <a href="http://www.math.washington.edu/~grunbaum/A%20Relative%20of%20Napoleons%20Theorem.pdf">"A relative of "Napoleon's theorem""</a> (PDF). Geombinatorics. 10: 116–121. Retrieved 25 April 2012.</li>
<li>Katrien Vandermeulen; et al. <a href="https://web.archive.org/web/20120830223350/http://mathsforeurope.digibel.be/Napoleon2.html">"Napoleon, a mathematician ?"</a>. Maths for Europe. Archived from <a href="http://mathsforeurope.digibel.be/Napoleon2.html">the original</a> on 30 August 2012. Retrieved 25 April 2012.</li>
<li><a href="/facts/Alexander_Bogomolny/WLgV43jd">Bogomolny, Alexander</a>. <a href="http://www.cut-the-knot.org/ctk/Napolegon.shtml">"Napoleon's Theorem"</a>. Cut The Knot! An interactive column using Java applets. Retrieved 25 April 2012.</li>
<li><a href="https://web.archive.org/web/20120121184926/http://www.pballew.net/napthm.html">"Napoleon's Thm and the Napoleon Points"</a>. Archived from the original on 21 January 2012. Retrieved 24 April 2012.</li>
<li>Weisstein, Eric W. <a href="http://mathworld.wolfram.com/NapoleonPoints.html">"Napoleon Points"</a>. From MathWorld—A Wolfram Web Resource. Retrieved 24 April 2012.</li>
<li>Philip LaFleur. <a href="https://web.archive.org/web/20120907233007/http://scimath.unl.edu/MIM/files/MATExamFiles/LaFleur%20Expository_FINAL.pdf">"Napoleon's Theorem"</a> (PDF). Archived from <a href="http://scimath.unl.edu/MIM/files/MATExamFiles/LaFleur%20Expository_FINAL.pdf">the original</a> (PDF) on 7 September 2012. Retrieved 24 April 2012.</li>
<li>Wetzel, John E. (April 1992). <a href="https://web.archive.org/web/20140429191842/http://apollonius.math.nthu.edu.tw/d1/disk5/js/geometry/napoleon/9.pdf">"Converses of Napoleon's Theorem"</a> (PDF). Archived from <a href="http://apollonius.math.nthu.edu.tw/d1/disk5/js/geometry/napoleon/9.pdf">the original</a> (PDF) on 29 April 2014. Retrieved 24 April 2012.</li></ul>

<h2 id="references">References</h2>

<ol>
<li id="fn:1">Coxeter, H. S. M.; Greitzer, S. L. (1967). Geometry Revisited. Mathematical Association of America. pp. 61–64. <a href="https://archive.org/details/geometryrevisite00coxe" target="_blank">https://archive.org/details/geometryrevisite00coxe</a> <a href="#fnref:1" class="footnote-back-ref">↩</a></li>
<li id="fn:2">Rigby, J. F. (1988). "Napoleon revisited". Journal of Geometry. 33 (1–2): 129–146. doi:10.1007/BF01230612. MR 0963992. S2CID 189876799. <a href="/wiki/Doi_(identifier)" target="_blank">/wiki/Doi_(identifier)</a> <a href="#fnref:2" class="footnote-back-ref">↩</a></li>
<li id="fn:3">Kimberling, Clark. "Encyclopedia of Triangle Centers". Retrieved 2 May 2012. <a href="http://faculty.evansville.edu/ck6/encyclopedia/ETC.html" target="_blank">http://faculty.evansville.edu/ck6/encyclopedia/ETC.html</a> <a href="#fnref:3" class="footnote-back-ref">↩</a></li>
<li id="fn:4">Kimberling, Clark. "Encyclopedia of Triangle Centers". Retrieved 2 May 2012. <a href="http://faculty.evansville.edu/ck6/encyclopedia/ETC.html" target="_blank">http://faculty.evansville.edu/ck6/encyclopedia/ETC.html</a> <a href="#fnref:4" class="footnote-back-ref">↩</a></li>
<li id="fn:5">Eddy, R. H.; Fritsch, R. (June 1994). "The Conics of Ludwig Kiepert: A Comprehensive Lesson in the Geometry of the Triangle" (PDF). Mathematics Magazine. 67 (3): 188–205. doi:10.2307/2690610. JSTOR 2690610. Retrieved 26 April 2012. <a href="http://epub.ub.uni-muenchen.de/4550/1/Fritsch_Rudolf_4550.pdf" target="_blank">http://epub.ub.uni-muenchen.de/4550/1/Fritsch_Rudolf_4550.pdf</a> <a href="#fnref:5" class="footnote-back-ref">↩</a></li>
<li id="fn:6">Eddy, R. H.; Fritsch, R. (June 1994). "The Conics of Ludwig Kiepert: A Comprehensive Lesson in the Geometry of the Triangle" (PDF). Mathematics Magazine. 67 (3): 188–205. doi:10.2307/2690610. JSTOR 2690610. Retrieved 26 April 2012. <a href="http://epub.ub.uni-muenchen.de/4550/1/Fritsch_Rudolf_4550.pdf" target="_blank">http://epub.ub.uni-muenchen.de/4550/1/Fritsch_Rudolf_4550.pdf</a> <a href="#fnref:6" class="footnote-back-ref">↩</a></li>
<li id="fn:7">de Villiers, Michael (2009). Some Adventures in Euclidean Geometry. Dynamic Mathematics Learning. pp. 138–140. ISBN 9780557102952. <a href="9780557102952" target="_blank">9780557102952</a> <a href="#fnref:7" class="footnote-back-ref">↩</a></li>
<li id="fn:8">de Villiers, Michael (2009). Some Adventures in Euclidean Geometry. Dynamic Mathematics Learning. pp. 138–140. ISBN 9780557102952. <a href="9780557102952" target="_blank">9780557102952</a> <a href="#fnref:8" class="footnote-back-ref">↩</a></li>
<li id="fn:9">Coxeter, H. S. M.; Greitzer, S. L. (1967). Geometry Revisited. Mathematical Association of America. pp. 61–64. <a href="https://archive.org/details/geometryrevisite00coxe" target="_blank">https://archive.org/details/geometryrevisite00coxe</a> <a href="#fnref:9" class="footnote-back-ref">↩</a></li>
<li id="fn:10">Scriba, Christoph J (1981). "Wie kommt 'Napoleons Satz' zu seinem namen?". Historia Mathematica. 8 (4): 458–459. doi:10.1016/0315-0860(81)90054-9. <a href="https://doi.org/10.1016%2F0315-0860%2881%2990054-9" target="_blank">https://doi.org/10.1016%2F0315-0860%2881%2990054-9</a> <a href="#fnref:10" class="footnote-back-ref">↩</a></li>
</ol>

Napoleon points open-in-new

Napoleon points