The marble game - Assume two kids, Billy and Gabriela, collect marbles. Billy collects blue marbles and Gabriela green marbles. When they get together they play a game where they mix all their marbles in a bag and sample one randomly. If the sampled marble is green, then Gabriela wins and if it is blue then Billy wins. If
B
{\displaystyle B}
is the number of blue marbles and
G
{\displaystyle G}
is the number of green marbles in the bag, then the probability
P
(
Billy
≿
Gabriela
)
{\displaystyle \mathbb {P} ({\text{Billy}}\succsim {\text{Gabriela}})}
of Billy winning against Gabriela is
P
(
Billy
≿
Gabriela
)
=
B
B
+
G
=
e
ln
(
B
)
e
ln
(
B
)
+
e
ln
(
G
)
=
1
1
+
e
ln
(
G
)
−
ln
(
B
)
{\displaystyle \mathbb {P} ({\text{Billy}}\succsim {\text{Gabriela}})={\frac {B}{B+G}}={\frac {e^{\ln(B)}}{e^{\ln(B)}+e^{\ln(G)}}}={\frac {1}{1+e^{\ln(G)-\ln(B)}}}}
.
In this example, the marble game satisfies linear stochastic transitivity, where the comparison function
F
:
R
→
[
0
,
1
]
{\displaystyle F:\mathbb {R} \to [0,1]}
is given by
F
(
x
)
=
1
1
+
e
−
x
{\displaystyle F(x)={\frac {1}{1+e^{-x}}}}
and the merit function
μ
:
A
→
R
{\displaystyle \mu :{\mathcal {A}}\to \mathbb {R} }
is given by
μ
(
M
)
=
ln
(
M
)
{\displaystyle \mu (M)=\ln(M)}
, where
M
{\displaystyle M}
is the number of marbles of the player. This game happens to be an example of a Bradley–Terry model.
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Chatterjee, Sabyasachi; Mukherjee, Sumit (June 2019). "Estimation in Tournaments and Graphs Under Monotonicity Constraints". IEEE Transactions on Information Theory. 65 (6): 3525–3539. arXiv:1603.04556. doi:10.1109/tit.2019.2893911. ISSN 0018-9448. S2CID 54740089. /wiki/ArXiv_(identifier)
Oliveira, Ivo F.D.; Ailon, Nir; Davidov, Ori (2018). "A New and Flexible Approach to the Analysis of Paired Comparison Data". Journal of Machine Learning Research. 19: 1–29. http://www.jmlr.org/papers/v19/17-179.html