The Riesz transforms are given by a Fourier multiplier. Indeed, the Fourier transform of Rjƒ is given by
In this form, the Riesz transforms are seen to be generalizations of the Hilbert transform. The kernel is a distribution which is homogeneous of degree zero. A particular consequence of this last observation is that the Riesz transform defines a bounded linear operator from L2(Rd) to itself.1
This homogeneity property can also be stated more directly without the aid of the Fourier transform. If σs is the dilation on Rd by the scalar s, that is σsx = sx, then σs defines an action on functions via pullback:
The Riesz transforms commute with σs:
Similarly, the Riesz transforms commute with translations. Let τa be the translation on Rd along the vector a; that is, τa(x) = x + a. Then
For the final property, it is convenient to regard the Riesz transforms as a single vectorial entity Rƒ = (R1ƒ,...,Rdƒ). Consider a rotation ρ in Rd. The rotation acts on spatial variables, and thus on functions via pullback. But it also can act on the spatial vector Rƒ. The final transformation property asserts that the Riesz transform is equivariant with respect to these two actions; that is,
These three properties in fact characterize the Riesz transform in the following sense. Let T=(T1,...,Td) be a d-tuple of bounded linear operators from L2(Rd) to L2(Rd) such that
Then, for some constant c, T = cR.
Somewhat imprecisely, the Riesz transforms of f {\displaystyle f} give the first partial derivatives of a solution of the equation
where Δ is the Laplacian. Thus the Riesz transform of f {\displaystyle f} can be written as:
In particular, one should also have
so that the Riesz transforms give a way of recovering information about the entire Hessian of a function from knowledge of only its Laplacian.
This is now made more precise. Suppose that u {\displaystyle u} is a Schwartz function. Then indeed by the explicit form of the Fourier multiplier, one has
The identity is not generally true in the sense of distributions. For instance, if u {\displaystyle u} is a tempered distribution such that Δ u ∈ L 2 ( R d ) {\displaystyle \Delta u\in L^{2}(\mathbb {R} ^{d})} , then one can only conclude that
for some polynomial P i j {\displaystyle P_{ij}} .
Strictly speaking, the definition (1) may only make sense for Schwartz function f. Boundedness on a dense subspace of L2 implies that each Riesz transform admits a continuous linear extension to all of L2. ↩