Let the length scales be normalized with the plate length L {\displaystyle L} and the velocity scale by the free-stream velocity U {\displaystyle U} ; then the only parameter in the problem is the Reynolds number R e = U L / ν {\displaystyle Re=UL/\nu } . Let the origin ( x , y ) = ( 0 , 0 ) {\displaystyle (x,y)=(0,0)} of the coordinate system be located at the trailing edge of the plate. Further let ( u , v ) {\displaystyle (u,v)} be the non-dimensional velocity components, p {\displaystyle p} be the non-dimensional pressure field and ψ {\displaystyle \psi } be the non-dimensional stream function such that u = ∂ ψ / ∂ y {\displaystyle u=\partial \psi /\partial y} and v = − ∂ ψ / ∂ x {\displaystyle v=-\partial \psi /\partial x} . For shortness of notation, let us introduce the small parameter ε = 1 / R e 1 / 8 {\displaystyle \varepsilon =1/Re^{1/8}} . The coordinate for horizontal interaction and for the three decks can then be defined by10
As χ → − ∞ {\displaystyle \chi \to -\infty } (or x → 0 − {\displaystyle x\to 0^{-}} ), the solution should approach the asymptotic behaviour of the Blasius solution, which is given by
where f B ( η ) {\displaystyle f_{B}(\eta )} is the Blasisus function which satisfies f B ‴ + f B f B ″ = 0 {\displaystyle f_{B}'''+f_{B}f_{B}''=0} subjected to f B ( 0 ) = f B ′ ( 0 ) = f B ′ ( ∞ ) − 1 = 0 {\displaystyle f_{B}(0)=f_{B}'(0)=f_{B}'(\infty )-1=0} . As χ → + ∞ {\displaystyle \chi \to +\infty } (or x → 0 + {\displaystyle x\to 0^{+}} ), the solution should approach the asymptotic behaviour of the Goldstein's near wake, which is given by
where μ = 1.1321 {\displaystyle \mu =1.1321} and λ = 0.8789 {\displaystyle \lambda =0.8789} . The Goldstein's inner wake solution is not needed here.
The solution in the middle deck is found to be
where A ( χ ) {\displaystyle A(\chi )} is referred to as the displacement function and P ( χ ) {\displaystyle P(\chi )} is referred to as the pressure function, to be determined from the upper and lower deck problems. Note that the correction to the Blasius stream function is of the order ε {\displaystyle \varepsilon } , although the pressure perturbation is only order ε 2 . {\displaystyle \varepsilon ^{2}.}
In the upper deck, the solution is found to given by
where β = 1.2168 {\displaystyle \beta =1.2168} . Furthermore, the upper deck problem also provides the relation between the displacement and the pressure function as
in which p . v . {\displaystyle \mathrm {p.v.} } stands for Cauchy principal value. One may notice that the pressure function and the derivative of the displacement function (aka transverse velocity) forms a Hilbert transform pair.
In the lower deck, the solution is given by
where Ψ ( χ , ξ ) {\displaystyle \Psi (\chi ,\xi )} will satisfy a boundary-layer type equations driven by the pressure gradient d P / d χ {\displaystyle dP/d\chi } and the slip-velocity of order ε 2 {\displaystyle \varepsilon ^{2}} generated by the middle deck. It is convenient to introduce u ^ = ∂ Ψ / ∂ ξ {\displaystyle {\hat {u}}=\partial \Psi /\partial \xi } and v ^ = − ∂ Ψ / ∂ χ {\displaystyle {\hat {v}}=-\partial \Psi /\partial \chi } , where u ^ {\displaystyle {\hat {u}}} and v ^ {\displaystyle {\hat {v}}} must satisfy
These equations are subjected to the conditions
where α = 1.6552 {\displaystyle \alpha =1.6552} . The displacement function A ( χ ) {\displaystyle A(\chi )} and therefore P ( χ ) {\displaystyle P(\chi )} must be obtained as part of the solution. The above set of equations may resemble normal boundary-layer equations, however it has an elliptic character since the pressure gradient term now is non-local, i.e., the pressure gradient at a location χ {\displaystyle \chi } depends on other locations as well. Because of this, these equations are sometimes referred to as the interactive boundary-layer equations. The numerical solution of these equations were obtained by Jobe and Burggraf in 1974.11
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