In measure theory, given a measurable space ( X , Σ ) {\displaystyle (X,\Sigma )} and a signed measure μ {\displaystyle \mu } on it, a set A ∈ Σ {\displaystyle A\in \Sigma } is called a positive set for μ {\displaystyle \mu } if every Σ {\displaystyle \Sigma } -measurable subset of A {\displaystyle A} has nonnegative measure; that is, for every E ⊆ A {\displaystyle E\subseteq A} that satisfies E ∈ Σ , {\displaystyle E\in \Sigma ,} μ ( E ) ≥ 0 {\displaystyle \mu (E)\geq 0} holds.
Similarly, a set A ∈ Σ {\displaystyle A\in \Sigma } is called a negative set for μ {\displaystyle \mu } if for every subset E ⊆ A {\displaystyle E\subseteq A} satisfying E ∈ Σ , {\displaystyle E\in \Sigma ,} μ ( E ) ≤ 0 {\displaystyle \mu (E)\leq 0} holds.
Intuitively, a measurable set A {\displaystyle A} is positive (resp. negative) for μ {\displaystyle \mu } if μ {\displaystyle \mu } is nonnegative (resp. nonpositive) everywhere on A . {\displaystyle A.} Of course, if μ {\displaystyle \mu } is a nonnegative measure, every element of Σ {\displaystyle \Sigma } is a positive set for μ . {\displaystyle \mu .}
In the light of Radon–Nikodym theorem, if ν {\displaystyle \nu } is a σ-finite positive measure such that | μ | ≪ ν , {\displaystyle |\mu |\ll \nu ,} a set A {\displaystyle A} is a positive set for μ {\displaystyle \mu } if and only if the Radon–Nikodym derivative d μ / d ν {\displaystyle d\mu /d\nu } is nonnegative ν {\displaystyle \nu } -almost everywhere on A . {\displaystyle A.} Similarly, a negative set is a set where d μ / d ν ≤ 0 {\displaystyle d\mu /d\nu \leq 0} ν {\displaystyle \nu } -almost everywhere.