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Square number
Product of an integer with itself

In mathematics, a square number or perfect square is an integer that is the square of another integer, meaning the product of that integer multiplied by itself. For example, 9 equals 3×3 and is written as 3², pronounced “three squared” (exponentiation). Square numbers correspond to areas of squares, with units defined by a unit square. They are a type of figurate number, alongside cube numbers and triangular numbers. In the real number system, square numbers are non-negative because their square roots are integers. The nth square number is n², with 0² = 0. The concept extends to rational numbers, where squares are ratios of square integers.

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Examples

The squares (sequence A000290 in the OEIS) smaller than 602 = 3600 are:

02 = 0 12 = 1 22 = 4 32 = 9 42 = 16 52 = 25 62 = 36 72 = 49 82 = 64 92 = 81 102 = 100 112 = 121 122 = 144 132 = 169 142 = 196 152 = 225 162 = 256 172 = 289 182 = 324 192 = 361 202 = 400 212 = 441 222 = 484 232 = 529 242 = 576 252 = 625 262 = 676 272 = 729 282 = 784 292 = 841 302 = 900 312 = 961 322 = 1024 332 = 1089 342 = 1156 352 = 1225 362 = 1296 372 = 1369 382 = 1444 392 = 1521 402 = 1600 412 = 1681 422 = 1764 432 = 1849 442 = 1936 452 = 2025 462 = 2116 472 = 2209 482 = 2304 492 = 2401 502 = 2500 512 = 2601 522 = 2704 532 = 2809 542 = 2916 552 = 3025 562 = 3136 572 = 3249 582 = 3364 592 = 3481

The difference between any perfect square and its predecessor is given by the identity n2 − (n − 1)2 = 2n − 1. Equivalently, it is possible to count square numbers by adding together the last square, the last square's root, and the current root, that is, n2 = (n − 1)2 + (n − 1) + n.

Properties

The number m is a square number if and only if one can arrange m points in a square:

m = 12 = 1
m = 22 = 4
m = 32 = 9
m = 42 = 16
m = 52 = 25

The expression for the nth square number is n2. This is also equal to the sum of the first n odd numbers as can be seen in the above pictures, where a square results from the previous one by adding an odd number of points (shown in magenta). The formula follows: n 2 = ∑ k = 1 n ( 2 k − 1 ) . {\displaystyle n^{2}=\sum _{k=1}^{n}(2k-1).} For example, 52 = 25 = 1 + 3 + 5 + 7 + 9.

There are several recursive methods for computing square numbers. For example, the nth square number can be computed from the previous square by n2 = (n − 1)2 + (n − 1) + n = (n − 1)2 + (2n − 1). Alternatively, the nth square number can be calculated from the previous two by doubling the (n − 1)th square, subtracting the (n − 2)th square number, and adding 2, because n2 = 2(n − 1)2 − (n − 2)2 + 2. For example,

2 × 52 − 42 + 2 = 2 × 25 − 16 + 2 = 50 − 16 + 2 = 36 = 62.

The square minus one of a number m is always the product of m − 1 {\displaystyle m-1} and m + 1 ; {\displaystyle m+1;} that is, m 2 − 1 = ( m − 1 ) ( m + 1 ) . {\displaystyle m^{2}-1=(m-1)(m+1).} For example, since 72 = 49, one has 6 × 8 = 48 {\displaystyle 6\times 8=48} . Since a prime number has factors of only 1 and itself, and since m = 2 is the only non-zero value of m to give a factor of 1 on the right side of the equation above, it follows that 3 is the only prime number one less than a square (3 = 22 − 1).

More generally, the difference of the squares of two numbers is the product of their sum and their difference. That is, a 2 − b 2 = ( a + b ) ( a − b ) {\displaystyle a^{2}-b^{2}=(a+b)(a-b)} This is the difference-of-squares formula, which can be useful for mental arithmetic: for example, 47 × 53 can be easily computed as 502 − 32 = 2500 − 9 = 2491. A square number is also the sum of two consecutive triangular numbers. The sum of two consecutive square numbers is a centered square number. Every odd square is also a centered octagonal number.

Another property of a square number is that (except 0) it has an odd number of positive divisors, while other natural numbers have an even number of positive divisors. An integer root is the only divisor that pairs up with itself to yield the square number, while other divisors come in pairs.

Lagrange's four-square theorem states that any positive integer can be written as the sum of four or fewer perfect squares. Three squares are not sufficient for numbers of the form 4k(8m + 7). A positive integer can be represented as a sum of two squares precisely if its prime factorization contains no odd powers of primes of the form 4k + 3. This is generalized by Waring's problem.

In base 10, a square number can end only with digits 0, 1, 4, 5, 6 or 9, as follows:

  • if the last digit of a number is 0, its square ends in 00;
  • if the last digit of a number is 1 or 9, its square ends in an even digit followed by a 1;
  • if the last digit of a number is 2 or 8, its square ends in an even digit followed by a 4;
  • if the last digit of a number is 3 or 7, its square ends in an even digit followed by a 9;
  • if the last digit of a number is 4 or 6, its square ends in an odd digit followed by a 6; and
  • if the last digit of a number is 5, its square ends in 25.

In base 12, a square number can end only with square digits (like in base 12, a prime number can end only with prime digits or 1), that is, 0, 1, 4 or 9, as follows:

  • if a number is divisible both by 2 and by 3 (that is, divisible by 6), its square ends in 0, and its preceding digit must be 0 or 3;
  • if a number is divisible neither by 2 nor by 3, its square ends in 1, and its preceding digit must be even;
  • if a number is divisible by 2, but not by 3, its square ends in 4, and its preceding digit must be 0, 1, 4, 5, 8, or 9; and
  • if a number is not divisible by 2, but by 3, its square ends in 9, and its preceding digit must be 0 or 6.

Similar rules can be given for other bases, or for earlier digits (the tens instead of the units digit, for example). All such rules can be proved by checking a fixed number of cases and using modular arithmetic.

In general, if a prime p divides a square number m then the square of p must also divide m; if p fails to divide ⁠m/p⁠, then m is definitely not square. Repeating the divisions of the previous sentence, one concludes that every prime must divide a given perfect square an even number of times (including possibly 0 times). Thus, the number m is a square number if and only if, in its canonical representation, all exponents are even.

Squarity testing can be used as alternative way in factorization of large numbers. Instead of testing for divisibility, test for squarity: for given m and some number k, if k2 − m is the square of an integer n then kn divides m. (This is an application of the factorization of a difference of two squares.) For example, 1002 − 9991 is the square of 3, so consequently 100 − 3 divides 9991. This test is deterministic for odd divisors in the range from kn to k + n where k covers some range of natural numbers k ≥ m . {\displaystyle k\geq {\sqrt {m}}.}

A square number cannot be a perfect number.

The sum of the n first square numbers is ∑ n = 0 N n 2 = 0 2 + 1 2 + 2 2 + 3 2 + 4 2 + ⋯ + N 2 = N ( N + 1 ) ( 2 N + 1 ) 6 . {\displaystyle \sum _{n=0}^{N}n^{2}=0^{2}+1^{2}+2^{2}+3^{2}+4^{2}+\cdots +N^{2}={\frac {N(N+1)(2N+1)}{6}}.} The first values of these sums, the square pyramidal numbers, are: (sequence A000330 in the OEIS)

0, 1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015, 1240, 1496, 1785, 2109, 2470, 2870, 3311, 3795, 4324, 4900, 5525, 6201...

The sum of the first odd integers, beginning with one, is a perfect square: 1, 1 + 3, 1 + 3 + 5, 1 + 3 + 5 + 7, etc. This explains Galileo's law of odd numbers: if a body falling from rest covers one unit of distance in the first arbitrary time interval, it covers 3, 5, 7, etc., units of distance in subsequent time intervals of the same length. From s = u t + 1 2 a t 2 {\displaystyle s=ut+{\tfrac {1}{2}}at^{2}} , for u = 0 and constant a (acceleration due to gravity without air resistance); so s is proportional to t2, and the distance from the starting point are consecutive squares for integer values of time elapsed.2

The sum of the n first cubes is the square of the sum of the n first positive integers; this is Nicomachus's theorem.

All fourth powers, sixth powers, eighth powers and so on are perfect squares.

A unique relationship with triangular numbers T n {\displaystyle T_{n}} is: ( T n ) 2 + ( T n + 1 ) 2 = T ( n + 1 ) 2 {\displaystyle (T_{n})^{2}+(T_{n+1})^{2}=T_{(n+1)^{2}}}

Odd and even square numbers

Squares of even numbers are even, and are divisible by 4, since (2n)2 = 4n2. Squares of odd numbers are odd, and are congruent to 1 modulo 8, since (2n + 1)2 = 4n(n + 1) + 1, and n(n + 1) is always even. In other words, all odd square numbers have a remainder of 1 when divided by 8.

Every odd perfect square is a centered octagonal number. The difference between any two odd perfect squares is a multiple of 8. The difference between 1 and any higher odd perfect square always is eight times a triangular number, while the difference between 9 and any higher odd perfect square is eight times a triangular number minus eight. Since all triangular numbers have an odd factor, but no two values of 2n differ by an amount containing an odd factor, the only perfect square of the form 2n − 1 is 1, and the only perfect square of the form 2n + 1 is 9.

Special cases

  • If the number is of the form m5 where m represents the preceding digits, its square is n25 where n = m(m + 1) and represents digits before 25. For example, the square of 65 can be calculated by n = 6 × (6 + 1) = 42 which makes the square equal to 4225.
  • If the number is of the form m0 where m represents the preceding digits, its square is n00 where n = m2. For example, the square of 70 is 4900.
  • If the number has two digits and is of the form 5m where m represents the units digit, its square is aabb where aa = 25 + m and bb = m2. For example, to calculate the square of 57, m = 7 and 25 + 7 = 32 and 72 = 49, so 572 = 3249.
  • If the number ends in 5, its square will end in 5; similarly for ending in 25, 625, 0625, 90625, ... 8212890625, etc. If the number ends in 6, its square will end in 6, similarly for ending in 76, 376, 9376, 09376, ... 1787109376. For example, the square of 55376 is 3066501376, both ending in 376. (The numbers 5, 6, 25, 76, etc. are called automorphic numbers. They are sequence A003226 in the OEIS.3)
  • In base 10, the last two digits of square numbers follow a repeating pattern mirrored symmetrical around multiples of 25. In the example of 24 and 26, both 1 off from 25, 242 = 576 and 262 = 676, both ending in 76. In general, ( 25 n + x ) 2 − ( 25 n − x ) 2 = 100 n x {\textstyle (25n+x)^{2}-(25n-x)^{2}=100nx} . An analogous pattern applies for the last 3 digits around multiples of 250, and so on. As a consequence, of the 100 possible last 2 digits, only 22 of them occur among square numbers (since 00 and 25 are repeated).

See also

Notes

Further reading

References

  1. Some authors also call squares of rational numbers perfect squares. /wiki/Rational_numbers

  2. Olenick, Richard P.; Apostol, Tom M.; Goodstein, David L. (2008-01-14). The Mechanical Universe: Introduction to Mechanics and Heat. Cambridge University Press. p. 18. ISBN 978-0-521-71592-8. 978-0-521-71592-8

  3. Sloane, N. J. A. (ed.). "Sequence A003226 (Automorphic numbers: n^2 ends with n.)". The On-Line Encyclopedia of Integer Sequences. OEIS Foundation. /wiki/Neil_Sloane